Answer:
the acceleration is reduced by gravity
a = (15 / .35) - [9.8 * sin(65º)]
Explanation:
break the launch vector into two components, vertical and horizontal
Force Net Vertical=-9.8*.350+15cos65 N
force net horizonal=15sin65
initial acceleration= force/mass= (-9.8+15/.350*cos65)j+(15/.350*sin65)i
using i,j vectors..
39 m/s²
initial Velocity (u) = 9m/s
acceleration (a) = 1.5m/s²
time(t) = 20s
V=u + at
V=9 + 1.5(20)
V=9 + 30
V=39m/s
Static Electricity
I think this is what your asking
