It shows the ray passing through the boundary.
Answer:
j
Explanation:
x = 4 t^2 - 2 t - 4.5
Position at t = 3 s
x = 4 (3)^2 - 2 (3) - 4.5 = 25.5 m
Velocity at t = 3 s
v = dx / dt = 8 t - 2
v ( t = 3 s) = 8 x 3 - 2 = 22 m/s
Acceleration at t = 3 s
a = dv / dt = 8
a ( t = 3 s ) = 8 m/s^2
When is the velocity = 0
v = 0
8 t - 2 = 0
t = 0.25 second
When is the position = 0
x = 0
4 t^2 - 2 t - 4.5 = 0

t = 1.4 second
Answer:
0.0001501 m
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
k = Spring constant = 
x = Compression of spring
F = Force = Mg
Mass of passengers

Each spring supports the following mass

Force of spring

The car moves down by 0.0001501 m
Answer: 50 m
Consider the figure below: Let O be the starting reference point. The boy runs northwards 125 m and then 75 m southwards.
Displacement is the shortest path traveled from the reference point. Distance is the total path length traveled. Hence, the distance would be 125 +75 =200 m but the displacement would be
.