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sineoko [7]
3 years ago
6

There are two planets: Planet A and Planet B. Both planets are the same size but Planet B is twice the mass of Planet A. Which o

ne would you expect to have a stronger pull gravity on its surface? Explain. *
Physics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

Planet B

Explanation:

The strength of the gravitational field on the surface of a planet is given by the equation:

g=\frac{GM}{R^2} (1)

where:

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

In this problem, we have two planets, A and B.

The two planets have same radius, R, while they have different masses, in particular

M_B=2M_A

So, the mass of planet B is twice the mass of planet A.

Looking at the eq.(1), we see that the gravitational field strength is proportional to the mass of the planet: therefore, the larger the mass, the greater the field strength.

So, since planet B has larger mass, then its gravity will be stronger than planet A.

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gtnhenbr [62]
The answer should be c
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3 years ago
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I just don't know how to do the question (a) and (b)​
ozzi

Using the equation

F=ma

we can observe that you have to apply a non-zero net force to an object in order to make it accelerate. In fact, if the net force is zero you have

0=ma \iff a=0

Since we're assuming n\neq 0

Now, if the 12N force is applied, the object moves with a constant speed. A constant speed means no acceleration, since by definition the acceleration is a change in speed.

If this sounds counterintuitive to you (why I'm applying a force but I have to acceleration?) think of when we drive a car: even if you want to keep your speed constant, you still have to use the gas pedal, just enough so that the push of the motor balances exactly the road/wheels friction. If you give less gas, the friction becomes stronger, and the car slows down. If you give more gas, the motor push becomes stronger, and the car accelerates.

Back to your exercise: constant speed means to acceleration, so the net force must be zero. This implies that the friction force is exactly 12N.

If the force is increased to 18N, there will be a net force of 6N pushing the object, causing it to accelerate. Using again the same equation of before, and plugging the 3kg mass in the equation, we have

F=ma \iff 6=3a \iff a=2

So, the object moves with constant acceleration and initial speed of 10m/s for 0.2 seconds. It's final speed will be

v = v_0+at = 10+2\cdot 0.2 = 10.4

5 0
4 years ago
Electrons in a particle beam each have a kinetic energy of 4.0 × 10 −17 J. What is the magnitude of the electric field that will
Dmitry_Shevchenko [17]

Answer:

-833.3 N/C

Explanation:

Kinetic energy, K, in terms of electric field, E, is given as:

K = qEr

q = charge = e = 1.6 × 10⁻¹⁹C

E = Electric field

r = distance = 0.3m

The electric field can be gotten by making E subject of formula:

E = K/(qr)

The electeic field needed to stop the electrons must be equal in magnitude to the electric field carried by these electrons:

E = (4.0 × 10⁻¹⁷)/(-1.6 × 10⁻¹⁹ * 0.3)

E = -833.3 N/C

This is the electric field needed to stop the electrons.

The negative sign means that the electric field must be in a direction opposite to the motion of the electrons.

3 0
3 years ago
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What’s is the movement of one object around another
allsm [11]

Answer:

revolution

Explanation:

8 0
3 years ago
A sinusoidal traveling wave is generated on a string by an oscillating source that completes 116 cycles per minute. What is the
slava [35]

Answer:

\lambda =6.32\ cm

Explanation:

given,

number of cycle complete (f) = 116 cycles per minute

wavelength observed at 11 m in 1.5 m.

v = \dfrac{distance}{time}

v = \dfrac{11}{1.5}

v = 7.33 m/s

\lambda = \dfrac{v}{f}

\lambda = \dfrac{7.33}{116}

\lambda =0.0632\ m

\lambda =6.32\ cm

The wavelength of the wave is equal to \lambda =6.32\ cm

6 0
3 years ago
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