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victus00 [196]
3 years ago
7

How much heat is absorbed during production of 127g of NO by the combination of nitrogen and oxygen?

Chemistry
1 answer:
Makovka662 [10]3 years ago
6 0
137 g NO) / (30.0061 g NO/mol)x (43kcal / 2 mil NO) = 98kcal
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describe how knowledge of the periodic table would be important in three different careers, based on what you’ve read.
ANEK [815]

The knowledge of periodic table would be important in these three different careers such as medicine, pharmacology and engineering.

<h3>What is the importance of periodic table in following careers?</h3>

Periodic table is organised the whole elements vertically in groups and horizontally in periods with increasing atomic number.

The knowledge of arrangement of these elements serves alot of purposes in the following three different careers:

  • Medicine: The element, iron is an important metal in the periodic table used in treatment of low blood levels.

  • Pharmacology: The transition metals are useful in the field of pharmacology for the production of drugs. Example of such elements are chromium, manganese, cobalt, nickel, copper, and molybdenum.

  • Engineering: The information of elements in the periodic table helps engineers in designing of materials used for constructions.

Therefore, the knowledge of periodic table is very important in these three different careers such as medicine, pharmacology and engineering.

Learn more about period table here:

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5 0
2 years ago
The average propane cylinder for a residential grill holds approximately 18 kg of propane. How much energy (in kJ) is released b
brilliants [131]
Combustion is a chemical reaction between a fuel and an oxidant, oxygen, to give off combustion products and heat. Complete combustion results when all of the fuel is consumed to form carbon dioxide and water, as in the case of a hydrocarbon fuel. Incomplete combustion results when insufficient oxygen reacts with the fuel, forming soot and carbon monoxide. 

The complete combustion of propane proceeds through the following reaction:
C_{3} H_{8} + 5O_{2} --> 3CO_{2} + 4H_{2}O

Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic. 

The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.

 14.50 kg propane  x <u> 1000 g </u> x <u>  1 mole propane   </u>  x <u>  2220 kJ  </u>   
                                     1 kg              44.1 g                     1 mole

= 729,931.97 kJ
8 0
2 years ago
After severe dust storms in the 1930s, practices were put in place to reduce soil erosion. Which
timurjin [86]

Answer: Farmers were paid to practice soil-conserving techniques like crop rotation and terracing

Explanation:

read about it here: https://www.pbs.org/wgbh/americanexperience/features/dust-bowl-surviving-dust-bowl/

5 0
2 years ago
Read 2 more answers
How is 1 hectoliter different from 1 kiloliter?
LUCKY_DIMON [66]
1 hectoliter is 26.4172

1 kiloliter is 264.172
5 0
3 years ago
Read 2 more answers
1. Using the Slater rule, determine the effective nuclear charge of platinum.
AleksandrR [38]

Answer:

Z* = 3.55

Explanation:

Slater rule says that:

Z*= Z - S

Z* be the nuclear effective charge

Z is the nuclear charge

S is the shielding constant

First we write the electronic configuration of platinum:1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 4f^{14} 5d^{9} 6s^{1}

The first Slater rule says that we need to group:

(1s^{2}) (2s, 2p)^{8} (3s, 3p)^{8} (3d^{10}) (4s, 4p)^{8} (4d^{10}) (5s, 5p)^{8} (4f^{14}) (5d^{9}) (6s^{1})

The second rule says that the electrons to the right are not shielding, but we are going to solve the exercise for the last level (6s), so we don't have electrons to the right.

For the third rule we have two considerations, if is ns or np and if is nd or nf:

For our case, we have an electro that is in ns, so the rule says that

-electrons within same group shield 0.35, except the 1s which shield 0.30

-electrons within the n-1 group shield 0.85

-electrons within the n-2 or lower groups shield 1.00

Now we can proceed with the calculation:

The first consideration in the third rule does not apply as we only have one electron on this level.

The second consideration will be as follow for the level 5, where we have 17 electrons.

Finally the third consideration will be for levels 1, 2, 3 and 4, where we have 14 for 4f, 10 for 4d, 8 for 4s and 4p, 10 for 3d, 8 for 3s and 3p, 8 for 2s and 2p and finally 2 for 1s, which gives 60 electrons.

So the result for S=(60*1.00 + 17*0.85) = 74.45

And the equation is: Z* = 78 - 74.45

So Z* = 3.55

3 0
3 years ago
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