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victus00 [196]
3 years ago
7

How much heat is absorbed during production of 127g of NO by the combination of nitrogen and oxygen?

Chemistry
1 answer:
Makovka662 [10]3 years ago
6 0
137 g NO) / (30.0061 g NO/mol)x (43kcal / 2 mil NO) = 98kcal
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One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
Rudiy27

Answer:

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Explanation:

Hello!

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

M_2O+H_2 \rightarrow 2M+H_2O

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

5.00gM_2O*\frac{1molM_2O}{(2x+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{xgM}{1molM}   = 2.32gM

Thus, we perform the operations in order to obtain:

\frac{10x}{2x+16}=2.32

So we solve for x as shown below:

10x = 2.32(2x+16)\\\\10x = 4.64x+37.12\\\\x = \frac{37.12}{10-4.64}\\\\x= 6.93 g/mol

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.

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