equation is balanced when the number of molecules are the equal in both reacting side and the product side.
Li(s) + n2(g) ---> Li3n(s)
From the equation above the reaction is not balanced since the molecules are not equal in both reacting side and the product side.
The reaction is balanced by adding 6 in front of Li and 2 infront of Li3n
that is
6Li(s) + n2(g)-----> 2Li3n(s)
Answer:
0.41kg/sec
Explanation:
PV= nRT
Given : V= 505 L
P=0.88 atm
R= 0.08206 Latm/K*mol
T= 172 .0C = 172+273 = 445 K
n = PV /RT = 0.88 * 505 / 0.08206 * 445 = 12.17 moles per sec of N2 are consumed
As per reaction : N2 + 3H2 ----> 2NH3
1 mole N2 is consumed to produce 2 moles NH3
moles of NH3 produced per sec :
(2 moles NH3/1mol N2) * 12.17 moles N2 = 24.34 moles NH3 per sec
grams of NH3 produced per sec =
24.34 moles NH3 per sec * molar mass NH3 = 24.34 moles NH3 per sec * 17.031 g/mol = 414.5 g NH3 per sec
rate in Kg/sec = 414.5 g NH3 per sec * (1kg /1000g) = 0.4145 Kg/sec
= 0.41kg/sec
The increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.
<h3>What is equilibrium?</h3>
The equilibrium of the gas is based on the pressure of the gas. With the increase in pressure, the equilibrium moves towards making fewer molecules of gas.
The gas equilibrium is proportional to the equilibrium K.
Increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.
Learn more about equilibrium
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Answer:
Phosphorus Mineralization
Explanation:
Organisms are bound to die when they do, they undergo decomposition which breaks down complex organic matter into simpler organic matter. The simpler organic matter also undergoes other processes that result in the production of simple inorganic matter; One of such processes is Phosphorus mineralization, it is the process by which phosphorus contained in organic matter is converted to simple inorganic phosphates.
Hmmm hard to tell. Sorrry :(/((/(/
