Answer: The density of the material is 2.66 g/mL and it is likely this is made of Aluminum
Explanation:
The first step to know the material of the chunk of metal is to calculate its density. The general formula for density is P (density) =
. Moreover, in this case, it is known the mass is 37.28 g, but the volume is not directly provided. However, we know the water in the graduated cylinder had a volume of 20.0 mL and this increased to 34.0 mL when the chunk of metal is added, this means the volume of the metal is 14 mL (34.0 mL - 20.0 mL = 14 mL). Now let's calculate the density:
![P = 2.66 g/mL](https://tex.z-dn.net/?f=P%20%3D%202.66%20g%2FmL)
This means the density of this metal is 2.66 g/mL, which can be rounded as 2. 7 g/mL, and according to the chart, this is the density of aluminum. Therefore, this material of this chunk is aluminum.
Answer:
111 L
Explanation:
Calculation of moles of hydrogen gas:-
Mass of
= 18.6 g
Molar mass of
= 2.01588 g/mol
![Moles=\frac{Mass}{Molar\ mass}=\frac{18.6}{2.01588}\ mol=9.23\ mol](https://tex.z-dn.net/?f=Moles%3D%5Cfrac%7BMass%7D%7BMolar%5C%20mass%7D%3D%5Cfrac%7B18.6%7D%7B2.01588%7D%5C%20mol%3D9.23%5C%20mol)
According to the given reaction:-
![2C+2H_2+O_2\rightarrow CH_3COOH](https://tex.z-dn.net/?f=2C%2B2H_2%2BO_2%5Crightarrow%20CH_3COOH)
2 moles of hydrogen gas on reaction produces one mole of acetic acid gas.
So,
1 mole of hydrogen gas on reaction produces
mole of acetic acid gas.
Also,
9.23 mole of hydrogen gas on reaction produces
mole of acetic acid gas.
Moles of acetic acid gas = 4.615 moles
Given that:
Temperature = 35 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (35 + 273.15) K = 308.15 K
n = 4.615 moles
P = 1.05 atm
V = ?
Using ideal gas equation as:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
1.05 atm × V = 4.615 moles ×0.0821 L atm/ K mol × 308.15 K
<u>⇒V = 111 L</u>
A. Chemical engineers
hope it helped
true
We describe the luminescence spectral properties of CdS nanoparticles with multiphoton excitation. Three types of CdS nanoparticles were examined which were a CdS/dendrimer composite which displays high anisotropy, Cd2+-enriched nanoparticles which display two emission maxima, and polyphosphate-stabilized nanoparticles which display long wavelength emission. Illumination with long wavelengths near 700−790 nm resulted in two-photon excitation. Essentially the same emission spectra and intensity decays were observed with one-photon and two-photon excitation. Comparison with fluorescein indicates the NPs display large two-photon cross sections near 100 GM. The CdS/dendrimer and Cd2+-enriched CdS nanoparticles displayed large anisotropy values with two-photon excitation, substantially larger than with one-photon excitation. It appears that semiconductor nanoparticles are comparable to organic fluorophores which display the same spectral properties with one-photon and two-photon excitation.