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3 years ago

The complete process for learning through repetition is to read, write, say, rest and revisit the information. T or F.

2 answers:

8 0

I would say that the given statement above would be true. <span>The complete process for learning through repetition is to read, write, say, rest and revisit the information. All process are of equal importance in order to really learn something. Hope this answers the question. Have a nice day.</span>

Dima020 [189]3 years ago

4 0

Answer: The given statement is True.

Learning means change or modification in the behavior of an individual that is obtained by getting new information, knowledge, skills or different experiences throughout the life.

There can be different learning styles like visual ( using pictures and images), verbal ( like repetition or rehearsal), social ( in groups), logical ( using reasoning) that could be adopted by different individuals.

The information can be memorized through repetition of the information by continuously reading, writing, speaking, and revisiting it.

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Sam, whose mass is 78 kg , stands at the top of a 11-m-high, 110-m-long snow-covered slope. His skis have a coefficient of kinet

Valentin [98]

Answer:

v = 8.09 m/s

Explanation:

For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.

Let's calculate the energy

starting point. Higher

Em₀ = U = m gh

final point. To go down the slope

Em_f = K = ½ m v²

The work of the friction force is

W = fr L cos 180

to find the friction force let's use Newton's second law

Axis y

N - W_y = 0

N = W_y

X axis

Wₓ - fr = ma

let's use trigonometry

sin θ = y / L

sin θ = 11/110 = 0.1

θ = sin⁻¹ 0.1

θ = 5.74º

sin 5.74 = Wₓ / W

cos 5.74 = W_y / W

Wₓ = W sin 5.74

W_y = W cos 5.74

the formula for the friction force is

fr = μ N

fr = μ W cos θ

Work is friction force is

W_fr = - μ W L cos θ

Let's use the relationship of work with energy

W + ΔU = ΔK

-μ mg L cos 5.74 + (mgh - 0) = 0 - ½ m v²

v² = - 2 μ g L cos 5.74 +2 (gh)

v² = 2gh - 2 μ gL cos 5.74

let's calculate

v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74

v² = 215.6 -150.16

v = √65.44

v = 8.09 m/s

6 0

2 years ago

URGENT!!!! WILL GIVE BRAINLIEST!!!!!! 15 POINTS

Artyom0805 [142]

It's the angle made by the incident ray when it's perpendicular to the surface. (Perpendicular lines are the lines that form a graph or like a 90-degree angle)

3 0

3 years ago

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Star A and Star B have different apparent brightnesses but identical luminosities. Star A is 10 light years away from earth and

STALIN [3.7K]

intensity of a star is inversely depends on the square of the distance from the star

we can say it is given as

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

here we know that

$\frac{I_1}{I_2} = 36 times$

also we know that

$r_1 = 10 Ly$

now we will have

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

$36 = \frac{r_2^2}{10^2}$

$r_2 = 60 Ly$

so other star is at distance 60 Light years

8 0

3 years ago

Calculate the velocity of the bicyclist between 0 and 3 seconds.

hoa [83]

Answer:

is there an equasion it gives you?

Explanation:

need a little more info.

4 0

3 years ago

a light ray traveling in air enters a second medium and its speed slows to 1.71 × 10^8 meters per second. what is the absolute i

givi [52]

The absolute refractive index is equal to the speed of light of the wave in air divided by the speed of light in the second medium. This means that it is equal to 3 x10^8 / 1.71 x10^8. This means the answer is 1.75

8 0

3 years ago

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