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Mumz [18]
3 years ago
8

A skateboarder is standing at the top of a tall ramp waiting to begin a trip. The skateboarder has

Physics
1 answer:
Mnenie [13.5K]3 years ago
7 0
Has a skateboard. your gonna have to give more details the. that just one .
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Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the r
madam [21]

Answer: 0.3872m

Explanation:

q= 100nC -->  100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

E= K\frac{q}{r^{2} } --> r=\sqrt{\frac{kq}{E} } Despejas "r"

Resuelves

<h3>r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9}  C)}{6000N/C} }  (la x es por, no es una variable)</h3><h3>r= 0.3872983346m</h3>
4 0
3 years ago
Ferromagnetic materials-
QveST [7]

Answer:

materials which exhibit a spontaneous net magnetization at the atomic level, even in the absence of an external magnetic field.

Explanation:

When a material is placed within a magnetic field, the magnetic forces of the material's electrons will be affected. This effect is known as Faraday's Law of Magnetic Induction. However, materials can react quite differently to the presence of an external magnetic field. This reaction is dependent on a number of factors, such as the atomic and molecular structure of the material, and the net magnetic field associated with the atoms. The magnetic moments associated with atoms have three origins. These are the electron motion, the change in motion caused by an external magnetic field, and the spin of the electrons.

5 0
3 years ago
Any child is pushing a shopping cart at a speed of 1.5 m/s.how long will it take this child to push the cart down the aisle with
NARA [144]
1.5 m/s is the velocity. 9.3 m is the length of aisle, over which Distance will be covered. Time is demanded in which the child will move the cart over the aisle with 1.5 m/s. v=S/t and, t=S/v Put values, t=9.3/1.5=6.2 s
7 0
3 years ago
I NEED THIS ASAP!!! 20 points!
suter [353]
Gravitational potential energy=mass*gravitational acceleration*heightKinetic energy = 0.5*mass*velocity²Thus:K.E0.5*1*x²=12.5x²=12.5/(0.5*1)x=√12.5/(0.5*1)x=5
GPEmass*gravitational acceleration*height1*9.81*h=98h=98/(9.81*1)h= 9.98 J approximately, rounded 10meters
7 0
3 years ago
A racecar experiences a centripetal acceleration of 36.0 m/s2 as it travels at a constant speed of 27.0 m/s along a circular arc
alexdok [17]

Answer:

20.25 m

Explanation:

  • <u>Centripetal acceleration </u>is given by; the square of the velocity, divided by the radius of the circular path.

That is;

         <em><u>ac = v²/r</u></em>

<em>         </em><em><u> Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the  radius, m</u></em>

Therefore;

r = v²/ac

  = 27²/36

  = 20.25 m

Hence the radius is 20.25 meters

5 0
3 years ago
Read 2 more answers
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