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Mumz [18]
3 years ago
8

A skateboarder is standing at the top of a tall ramp waiting to begin a trip. The skateboarder has

Physics
1 answer:
Mnenie [13.5K]3 years ago
7 0
Has a skateboard. your gonna have to give more details the. that just one .
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which of these best dscribes Earth's mantle? A. most dense layer, consists of the outer and inner parts B. thinnest under the oc
stich3 [128]

C. middle layer, density increases with depth as pressure increases

Explanation:

The mantle is the middle layer of the earth. It's density increases with depth as pressure increases.

  • Based on the compositional division of the earth, our blue planet is divided into crust, mantle and the core.
  • The crust is the lightest and the outermost layer of the earth.
  • The mantle is the middle layer. Its density lies between that of the core and crust.
  • The mantle is the largest layer and density increases with depth here.
  • The core is a metallic ball. It is the most dense part of the earth.

Learn more:

Mantle brainly.com/question/10758534

#learnwithBrainly

6 0
3 years ago
Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a
jolli1 [7]

Answer:

Explanation:

Not enough information.

IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.

THEN

The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was

v = gt

vy₀ = 9.8(0.5)

vy₀ = 4.9 m/s

vsinθ = vy₀

v = vy₀/sinθ

v = 4.9/sin32

v = 9.2466...

v = 9.2 m/s

8 0
2 years ago
Which weather event is capable of destroying homes and uprooting trees due to a low pressure area at its center
Bond [772]

You're talking about a <em>tornado</em>.

It's not so much the low pressure that's so dangerous in the center of a tornado.  It's more a matter of the high winds that are <em>caused </em>by the low pressure.

7 0
3 years ago
Read 2 more answers
magine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and rad
DerKrebs [107]

Without counting wind resistance, They will both reach the ground at the same time. If we apply the concept of kinematics, such as the equation vf^2=vi^2 + 2ad. This equation doesn't count how big or how heavy the mass is, it only focuses on how fast where they in the start and how far are both of them from the ground. So if they both have the same distance and same initial veloctity, then they will reach the ground at the same time.

For example, Try dropping a pen and a paper(Vertically) at the same height, you'll see they'll reach the ground at the same time.

If you count wind resistance, the heavier ball will hit the ground faster, because the air molecules will resist the lighter ball compared to the heavier ball.

6 0
3 years ago
The following three hot samples have the same temperature. The same amount of heat is removed from each sample. Which one experi
melomori [17]

Complete Question:

The following three hot samples have the same temperature. The same amount of heat is removed from each sample. Which one experiences the smallest drop in temperature, and which one experiences the largest drop? Sample A: 4.0 kg of water [c = 4186 J/(kg·C°)] Sample B: 2.0 kg of oil [c = 2700 J/(kg·C°)] Sample C: 9.0 kg of dirt [c = 1050 J/(kg·C°)]

Answer:

A. Smallest B. Largest.

Explanation:

Assuming no heat exchange except for the heat removed from any sample (which we know is the same for the three ones), and that the process is done using only conduction, we can use the equation that relates the heat lost or gained by one object, with the mass of the object and the consequent change in temperature, as follows:

Q = c*m*ΔT, where c, is a proportionality constant called specific heat, which is different for each material.

As we know that the heat removed is the same for the three samples, we can equate the right sides of the equation for each sample, as follows:

cw*mw*ΔTw = co*mo*ΔTo = cd*md*ΔTd

Replacing by the givens, we have:

4.0 kg. 4,186 J/kgºC*ΔT(ºC) = 2.0 kg*2,700 J/kgºC*ΔT(ºC) =9.0kg*1,050J/kgºC*ΔT(ºC)

As the three expressions must be equal each other, it's clear that the unknown term (the drop in temperature) must compensate the product of the mass times the specific heat.

This product is the following for the three samples:

Water: 4.0 kg*4,186 J/kgºC = 16,744 J/ºC

Oil : 2.0 kg*2,700 J/kgºC    = 5,400 J/ºC

Dirt: 9.0 * 1,050 J/kgºC        = 9,450 J/ºC

Clearly, we see that in order to keep the heat exchange equations equal each other, the water must suffer the smallest drop in temperature, and the oil must experience the largest one.

So, the sample A experiencies the smallest drop in temperature, and sample B does the largest one.

5 0
2 years ago
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