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4 years ago

14

HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the gro

und. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy

1 answer:

fenix001 [56]4 years ago

5 0

Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy

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Calculate the electric field at the center of a square

pantera1 [17]

Answer:

$E_y=1175510.2\ N.C^{-1}$

The Magnitude of electric field is in the upward direction as shown directly towards the charge $q_1$ .

Explanation:

Given:

side of a square, $a=52.5\ cm$

charge on one corner of the square, $q_1=+45\times 10^{-6}\ C$

charge on the remaining 3 corners of the square, $q_2=q_3=q_4=-27\times 10^{-6}\ C$

<u>Distance of the center from each corners</u> $=\frac{1}{2} \times diagonals$

$diagonal=\sqrt{52.5^2+52.5^2}$

$diagonal=74.25\cm=0.7425\ m$

∴Distance of center from corners, $b=0.3712\ m$

Now, electric field due to charges is given as:

$E=\frac{1}{4\pi\epsilon_0}\times \frac{q}{b^2}$

<u>For charge $q_1$ we have the field lines emerging out of the charge since it is positively charged:</u>

$E_1=9\times 10^9\times \frac{45\times 10^{-6}}{0.3712^2}$

$E_1=2938775.5\ N.C^{-1}$

<u>Force by each of the charges at the remaining corners:</u>

$E_2=E_3=E_4=9\times 10^9\times \frac{27\times 10^{-6}}{0.3712^2}$

$E_2=E_3=E_4=1763265.3\ N.C^{-1}$

<u> Now, net electric field in the vertical direction:</u>

$E_y=E_1-E_4$

$E_y=1175510.2\ N.C^{-1}$

<u>Now, net electric field in the horizontal direction:</u>

$E_y=E_2-E_3$

$E_y=0\ N.C^{-1}$

So the Magnitude of electric field is in the upward direction as shown directly towards the charge $q_1$ .

8 0

3 years ago

Two train whistles, and , each have a frequency of 392 Hz. is stationary and is moving toward the right (away from ) at a speed

trasher [3.6K]

Answer:

Part a)

f = 371.1 Hz

Part b)

f = 417.7 Hz

Part c)

beat frequency = 46.6 Hz

Explanation:

Part a)

Due to doppler's Effect the frequency of the sound heard by the train which is moving away from the observer is given as

$f_1 = f_0\frac{v + v_o}{v + v_s}$

$f_1 = 392(\frac{340 + 15}{340 + 35})$

$f_1 = 371.1 Hz$

Part b)

Now from the second train which is approaching the person we can say

$f_2 = f_0\frac{v - v_o}{v - v_s}$

$f_2 = 392(\frac{340 - 15}{340 - 35})$

$f_2 = 417.7 Hz$

Part c)

As we know that beat frequency is the difference in the frequency from two sources

$f_b = f_2 - f_1$

$f_b = 417.7 - 371.1 = 46.6 Hz$

8 0

3 years ago

Common sports injury : ankle sprain , bone fracture , muscle strain , neck low back pain , shoulder pain. First aid needed

erastova [34]

Answer:

m

Explanation:

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3 years ago

Forces can be________. What phrase completes the sentence.

koban [17]

Answer:

pushes or pulls

Explanation:

hope this helps....

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3 years ago

All living things are made of one or more cells.<br> True<br> False

dimulka [17.4K]

False because their are single cell organisms

7 0

3 years ago

Read 2 more answers