Ask question

Ask question

All categories

3 years ago

14

HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the gro

und. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy

1 answer:

fenix001 [56]3 years ago

5 0

Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy

You might be interested in

A typical adult human has a mass of about 70 kg.

Misha Larkins [42]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N

b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>

3 0

3 years ago

When a object slows down what direction is the force going?

trapecia [35]

Answer: when a object gets slowed down, it's force is either going into friction and drag, if it's on the ground, and weight+drag+friction, if it's in the air.

Explanation:

7 0

3 years ago

if the kinetic and potential energy in a system or equal to the potential energy increases what happens as a result

8090 [49]

Answer:If the kinetic and potential energy in a system are equal, then the potential energy increases. ... Stored energy decreases. Energy of motion decreases. Total energy decreases

Explanation:

8 0

3 years ago

You need to design a 60.0-Hz ac generator that has a maximum emf of 5500 V. The generator is to contain a 150-turn coil that has

olchik [2.2K]

Answer:

So magnetic field will be equal to 0.1144 T

Explanation:

We have given frequency f = 60 Hz

Maximum emf e = 5500 volt

Number of turns N = 150

Area $A=0.85m^2$

Emf generated in ac generator is given $e=NBA\omega sin(\omega t)$

For maximum emf $sin(\omega t)=1$

So maximum emf will be equal to $e=NBA\omega$

$B=\frac{e}{NA\omega }=\frac{5500}{150\times 2\times 3.14\times 60\times 0.85}=0.1144T$

So magnetic field will be equal to 0.1144 T

3 0

3 years ago

Over a span of 6.0 seconds, a car changes its speed from 89 km/h to 37 km/h. What is its average acceleration in meters per seco

faltersainse [42]

Answer: Average acceleration is -2.407 $\frac{m}{s^{2}}$

Explanation:

Average acceleration is equal to change in velocity divided by time taken

therefore, $a=\frac{Vf-Vi}{t}$

=> $a=\frac{37-89}{6}\times \frac{5}{18}\frac{m}{s^{2}} = -2.407 \frac{m}{s^{2}}$

6 0

4 years ago