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3 years ago

Define the following in your own words:

Physics

1 answer:

harina [27]3 years ago

6 0

Answer:

Explanation:

1. how hot or cold something is

2. Energy from heat

3. something hot

4. heat passing through objects

5. hot air rising and warm air lowering

6. heat you cant see but it still effects the environment

&. All of these vocabulary words relate beacuse they all have to do with temperature and how heat is conducted. Conduction, Convension, and radiation are all examples of this.

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Once carbon begins burning in the core of a high-mass star, the outer layers begin to fall inward, driving up the fusion rates a

sammy [17]

Answer:

Fusion rates and star evolution increase rapidly because of the conversion of hydrogen molecules to helium.

Explanation:

At the early stage of a star mass, hydrogen atoms are produced. After a few billion years, these hydrogen atoms formed at the core of the star mass begin to fuse on the external side of the core. Hydrogen atoms get rapidly fused, resulting to a contraction of the star core, and as more hydrogen atoms get fused, helium atoms are formed.

This action results into rapid into a rapid and violent burning action of hydrogen atoms around the core.

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3 years ago

Taking test, need physics help<br> ASAP please!

Neko [114]

Answer:

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3 years ago

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

mario62 [17]

<span>Weight is directly proportional to mass.</span>

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3 years ago

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ou see an image of yourself in a mirror because light waves are A) diffracted. B) reflected back at you. C) refracted through ai

Oksi-84 [34.3K]

The answer would be B) reflected back at you

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3 years ago

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Consider a ball of 0.22 kg, initially at rest, is dropped from an initial height of 1.80 m. It rebounds back after colliding wit

I am Lyosha [343]

Answer:

The impulse on the ball delivered by the floor is 2.52 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 0.22 kg

It is dropped from an initial height of 1.80 m. It rebounds back after colliding with the floor to a final height of 1.50 m. Initial velocity and final velocity can be calculated using conservation of energy as :

$u=\sqrt{2gh} \\\\u=\sqrt{2\times 10\times 1.8} \\\\u=6\ m/s$

Final velocity,

$v=\sqrt{2gh'} \\\\v=\sqrt{2\times 10\times 1.5} \\\\v=5.47\ m/s$

As the ball rebounds, v = -5.47 m/s

We need to find the impulse on the ball delivered by the floor. We know that impulse is equal to the change in momentum as follows :

$J=m(v-u)\\\\J=0.22\times ((-5.47)-6)\\\\J=-2.52\ kg-m/s$

So, the impulse on the ball delivered by the floor is 2.52 kg-m/s.

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3 years ago