Answer:
Spring Constant = 279.58 N/m
Explanation:
We are given;
Mass; m = 2.05 x 10^(-2) kg = 0.0205 kg
Distance of compression; x = 8.01 × 10^(-2) m = 0.0801 m
Maximum height; h = 4.46 m
The formula for the energy in the spring is given by;
E = ½kx²
where:
k is the spring constant
x is the distance the spring is compressed.
Now, this energy of the spring will be equal to the energy of the pellet at its highest point. Energy of pallet = mgh So;
½kx² = mgh
Plugging in the relevant values, we have;
½ * k * 0.0801² = 0.0205 * 9.81 * 4.46
0.003208005k = 0.8969
k = 0.8969/0.003208005
k = 279.58 N/m
Explanation:
The angle of the handle relative to the horizontal is 35°. The angle of the ramp to the horizontal is 7°. So the angle of the handle relative to the ramp is 28°.
cos 28° = 50 / F
F = 50 / cos 28°
F = 56.6 lbs
Answer:
326149.2 KJ
Explanation:
The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:
Q = m*cv*ΔT
Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.
A 65000 L swimming pool will have a mass of:
65000L * = 65000 kg
The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.
We replace the data and get:
Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ
Explanation:
Boyle's law can be stated as the "volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant". It is mathematically expressed as;
P1 V1 = P2 V2
P1 is the initial pressure
V1 is the initial volume
P2 is the final pressure
V2 is the final volume
Charles's law states that the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant.
It is mathematically expressed as;
=
V and T are volume and temperature respectively
1 and 2 are the initial and final states
(a) work=Fd
<span>345x24=8280J </span>
<span>(b) work=Force of friction*d </span>
<span>Force of friction =coefficient*normal force=.22x1.5x10^3=330 </span>
<span>330*d=7920J </span>
<span>(c) net work =8280-7920=360J</span>