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ICE Princess25 [194]
2 years ago
15

Can someone answer 8-11 please

Mathematics
1 answer:
vampirchik [111]2 years ago
6 0

Answer:

7.9

4.2

9.3

17.8

Step-by-step explanation:

8. √63

the square of 8 is 64 √63 is close to 64 so we can say it's 7.9 approximately

9. √18

the square of 4 is 16, √18 is greater than 16 so we can say it's 4.2 approximately

10. √87

the square of 9 is 81, √87 is greater than 81 so we can say the value of it is approximately 9.3

11. √319

the square of 18 is 324, √319 is smaller than 324 so we can say it's 17.8

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What is the common difference of the arithmetic sequence 5, 8, 11, 14?
AnnZ [28]

Answer:

The common difference is 3

Step-by-step explanation:

we know that

In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant called the common difference

we have

5,8,11,14

so

a1=5

a2=8

a3=11

a4=14

a2-a1=8-5=3

a3-a2=11-8=3

a4-a3=14-11=3

therefore

The common difference is 3

3 0
3 years ago
PLEASE HELP ME PLEASEEEEEEEEE
dolphi86 [110]
That answer I C. I hope this helps!!!!
8 0
2 years ago
Help please help I really need it
nalin [4]

Answer: x^2

Step-by-step explanation: x times x is x^2

3 0
2 years ago
Read 2 more answers
Inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has on
Sphinxa [80]

Answer:

5 length

Step-by-step explanation:

The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share  one side of the square  BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.

So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.

4 0
3 years ago
Which statement best explains the relationship between
-Dominant- [34]

Answer: They are not perpendicular because their slopes are  not negative reciprocals.

Step-by-step explanation:

For these two lines to be perpendicular, their slopes have to be negative reciprocals.

Slope of FG.

F = (-4, 1)

G = (0, -2)

= (Y₂ - Y₁) / (X₂ - X₁)

= (-2 - 1) / (0 + 4)

= -3/4

Slope of HJ

J = (0 , 4)

H = (-4, -2)

Slope =  (Y₂ - Y₁) / (X₂ - X₁)

= (-2 - 4) / (-4 -0)

= 6/4

= 3/2

<em>The slopes of these lines are not negative reciprocals so these lines are not perpendicular. </em>

4 0
3 years ago
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