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Alchen [17]
3 years ago
14

Which 3 are they? (will mark brainliest)

Chemistry
1 answer:
Paraphin [41]3 years ago
8 0

probably condensation and evaporation and freezing.. PROBABLY idk

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Select all that apply. The electron configurations of some elements are given. Based on the electron configurations which elemen
erma4kov [3.2K]

Answer:

correct option: A and D

Explanation:

generally element from d block can for ion with multiple charge and having incomplete outershell means element do not have fullfiled or half filed orbital because in these case it takes more energy to remove valence shell electron.

8 0
3 years ago
If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em
erica [24]

Answer: Wavelength  associated with the fifth line is 397 nm

Explanation:

E=\frac{hc}{\lambda}

\lambda = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant =10973731.6m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2

\frac{1}{\lambda}=2.52\times 10^{6}m

\lambda}=3.97\times 10^{-7}m=397 nm      1nm=10^{-9}m

Thus wavelength λ associated with the fifth line is 397 nm

7 0
4 years ago
In electrophilic aromatic substitution reactions the hydroxyl group is an o p-director because?
Natalka [10]

In electrophilic aromatic substitution reactions the hydroxyl group is an o,p-director because: hydroxyl group donates the electron density to the ring by induction and destabilizes the meta sigma complex and  by resonance and it  stabilizes the ortho and para sigma complexes of aromatic ring .

Most ring activators have atoms with unshared electron pairs directly attached to a carbon atom of the benzene ring . For example, the — OH group has two pairs of unshared electrons on the oxygen atom , which will form a bond to a carbon atom of the benzene ring . Thus , the — OH group will be an activating group in electrophilic aromatic substitution reactions .

to learn more about electrophilic aromatic substitution reactions please click here ,

brainly.com/question/28286554

#SPJ4

5 0
2 years ago
What mass of each solute is present in 294 g of a solution that contains 4.86% by mass NaCl and 7.54% by mass Na2CO3
Angelina_Jolie [31]
In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams

Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams
7 0
3 years ago
Can a mini fridge still be used if you break the freezer
Romashka [77]
The fridge part can, just not the freezer, I think.
8 0
4 years ago
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