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hichkok12 [17]
3 years ago
12

An object falls from a high building and hits the ground in 8.0 seconds. Ignoring air resistance, what is the distance that it f

ell?
Physics
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

310 meters

Explanation:

Given:

v₀ = 0 m/s

t = 8.0 s

a = -9.8 m/s²

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (8.0 s) + ½ (-9.8 m/s²) (8.0 s)²

Δy = -313.6

Rounded to two significant figures, the object fell 310 meters.

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A stone tumbles into a mine shaft and strikes bottom after falling for 4.2 second how deep is the mine shaft
rjkz [21]
4.2*9.8\\41.16

41.16 meters
5 0
3 years ago
A powerful motorcycle can produce an acceleration of 3.50 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting
IrinaK [193]

Answer:1265 N

Explanation:

Given

acceleration of motorcycle \left ( a\right )=3.5 m/s^2

Velocity \left ( v\right )=90 km/h\approx 25m/s

Air friction and Friction\left ( f\right )=425 N

mass of the motorcycle with rider\left ( m\right )=240 Kg

Applying Forces on motorcycle

F_{engine}-f=ma

F_{engine}=f+ma

F_{engine}=425+240\left ( 3.5\right )

F_{engine}=425+840=1265 N

5 0
3 years ago
A spaceship moves radially away from Earth with acceleration 29.4 m/s 2 (about 3g). How much time does it take for sodium street
Gemiola [76]

Answer:

doppler shift's formula for source and receiver moving away from each other:

<em>λ'=λ°√(1+β/1-β)</em>

Explanation:

acceleration of spaceship=α=29.4m/s²

wavelength of sodium lamp=λ°=589nm

as the spaceship is moving away from earth so wavelength of earth should increase w.r.t increasing speed until it vanishes at λ'=700nm

using doppler shift's formula:

<em>λ'=λ°√(1+β/1-β)</em>

putting the values:

700nm=589nm√(1+β/1-β)

after simplifying:

<em>β=0.17</em>

by this we can say that speed at that time is: v=0.17c

to calculate velocity at an acceleration of a=29.4m/s²

we suppose that spaceship started from rest so,

<em>v=v₀+at</em>

where v₀=0

so<em> v=at</em>

as we want to calculate t so:-

<em>t=v/a</em>                                                v=0.17c      ,c=3x10⁸           ,a=29.4m/s²

putting values:

=0.17(3x10⁸m/s)/29.4m/s²

<em>t=1.73x10⁶</em>

7 0
3 years ago
1. Vector B is multiplied by the scalar 921.5. What angle does the new vector make with the x-axis?
adelina 88 [10]
1. Is 49.5
2. Is 8.6
4. Is 6.6
Wait I’m not sure
6 0
3 years ago
Read 2 more answers
A 30 kg student drops down from the monkey bars. The acceleration due to gravity is -9.8 m/s^2. Neglecting air drag, what is the
Sholpan [36]

The net force on the student is A) -294 N

Explanation:

Neglecting air resistance, there is only one force acting on the student: the force of gravity, which is given by

F=mg

where

m is the mass of the student

g is the acceleration of gravity

In this problem, we have:

m = 30 kg is the mass of the student

g=-9.8 m/s^2 is the acceleration of gravity, where the negative sign means the direction is downward

Substituting, we find the force of gravity on the student:

F=(30)(-9.8)=-294 N

And since this is the only force acting on the student, it is also the net force on him.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

8 0
3 years ago
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