As the temperature of the lead and helium is the same. Thus the average kinetic energy is also the same for lead and helium.
Reason:
It is given that a 5.0-kg bar of lead is placed inside a 12-L chamber filled with helium gas. The temperature of the lead and helium is the same. It is required to compare the average kinetic energy of the lead atoms and helium atoms.
The average kinetic energy is calculated as,
.
Here K is the average kinetic energy, R is the gas constant, N is the Avogadro's number, and T is the temperature.
As the temperature is the same for both lead and helium. As a result, the average kinetic energy is also the same for lead and helium.
Learn more about average kinetic energy here,
brainly.com/question/1599923
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Titty milk I think because it taste amazing so you can go 21km/h
Displacement = (straight-line distance between the start point and end point) .
Since the road east is perpendicular to the road north,
the car drove two legs of a right triangle, and the magnitude
of its final displacement is the hypotenuse of the triangle.
Length of the hypotenuse = √ (215² + 45²)
= √ (46,225 + 2,025)
= √ 48,250
= 219.7 miles .
We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is

where

Now we find the moment of inertia by integrating from

to

The moment of inertia is

(from (-a/2) to

(a/2))
Answer:
I believe Mercury has the most extreme temperatures in the solar system, ranging from -280?F at night to 800 degrees F during the day for parts of the surface.
Hope that helps! :)