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astraxan [27]
1 year ago
13

a star has a distance of 30 parsecs and a apparent magnitude of 3 --what would its absolute magnitude be?

Physics
1 answer:
Alborosie1 year ago
8 0

The absolute magnitude of the star would be +5.

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A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?
bezimeni [28]

Answer:

45 J

Explanation:

The equation for work is:

Work=Force*Distance

We can substitute the given values into the equation:

Work=15N*3m\\Work=45Nm\\Work=45J

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2 years ago
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Westkost [7]

Answer:

4.15 m/s

Explanation:

Its given that acceleration is 0.1 m/s² with a direction opposite to the velocity. Since, the direction of acceleration is opposite to the velocity, this gives us a hint that the velocity is decreasing and so acceleration would be negative.

i.e.

acceleration = a = - 0.1 m/s²

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Velocity after covering 6 meters = Final velocity = v_{f} = 4 m/s

We need to find the initial speed, which will be the same as the magnitude of initial velocity.

Initial velocity = v_{i} =  ?

3rd equation of motion relates the acceleration, distance, final velocity and initial velocity as:

2aS = (v_{f})^{2}-(v_{i})^{2}

Using the known values in the formula, we get:

2(-0.1)(6)=(4)^{2}- (v_{i})^{2}\\\\ (v_{i})^{2}=16+1.2\\\\ (v_{i})^{2}=17.2\\\\ v_{i}=4.15

Thus, the initial speed of the ball was 4.15 m/s

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A car weighing 12,000 N is parked on a 36° slope. The car starts to roll down the hill. What is the acceleration of the car?​
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Explanation:

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