Molar mass :
NaBr = 103 g/mol
Pb(NO3)2 = 331.20 g/mol
<span><span /><span>Balanced chemical equation :
</span></span>2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr<span>2
</span><span>
2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
g NaBr -------------------> 311 g Pb(NO3)2
331.20 g = 2*103*311
331.20 g = 64066
mass ( NaBr ) = 64066 / 331.20
mass ( naBr) = 193,43 g of NaBr
hope this helps!.
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Answer:
The Persian Gulf and the Tigris and Euphrates
Explanation:
<h3>
Answer:</h3>
= +0.43 V
<h3>
Explanation:</h3>
The two standard reduction potentials are;
Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E₀ = +0.77 V
Cu²⁺(aq) + 2e⁻ → Cu(s) E₀ = +0.34 V
The overall reaction is;
Fe³⁺(aq) + Cu(s) → Fe²⁺(aq) + Cu²⁺(aq)
To calculate the standard cell potential of the overall reaction, we use the equation;
Ecell = E redu, cathode - E red, anode
From the reaction; Copper lost electrons to form copper ions (Cu²⁺) (Oxidation) while Fe³⁺ gained electrons to form Fe²⁺ (reduction)
Therefore;
E cell = + 0.77 v - (+0.34 v)
= + 0.43 V
Hence, the standard cell potential of the overall reaction is +0.43 V
V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l) is the balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The word based equation is
Vanadium(V) oxide + Hydrogen gas → Vanadium (III) oxide + Water
Now write the chemical equation
V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l)
<u>Reactant side</u> <u>Product side</u>
V = 2 V = 2
O = 5 O = 5
H = 4 H = 4
We can see that the number of atoms on reactant side is equal to the number of atoms on product side. So the given equation is balanced.
Thus from the above conclusion we can say that V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l) is the balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water.
Learn more about the Balanced chemical equation here: brainly.com/question/15355912
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