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fredd [130]
4 years ago
5

Be sure to answer all parts. Rubidium and bromine atoms are depicted at right. Answer the following questions. (a) What is the c

harge on the rubidium ion? What is the charge on the bromide ion? (b) To which noble gas is the rubidium ion related? To which noble gas is the bromide ion related? h5sil8102 (c) Which pair below best represents the relative ionic sizes?

Chemistry
1 answer:
finlep [7]4 years ago
6 0

The complete question is found on the image attached.

Answer:

a) Rb= +1, Br= -1

b)Bromide and rubidium ions are related to krypton

c) C

Explanation:

Rubidium is found in group 1 with a charge of +1. Bromine is found in group 17 with a charge of -1. Both species have the same configuration as krypton. The ionic sizes of the ions are a very similar to each other Rb+ is 166 while Be is 167.

This RbBr is an ionic compound.

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The neutrons take up most of the space of an atom
7 0
3 years ago
Read 2 more answers
GUYS I NEED HELP THIS IS DUE TONIGHT !!!
kenny6666 [7]

Explanation:

To balance the reactions given, we must understand that the principle to follow is the law of conservation of matter.

Based on this premise, the number of moles of species on the reactant and product side must be the same;

 

      Li   +   Br₂  →    LiBr

Put a,b and c as the coefficient of each species

   aLi  + bBr₂ → cLiBr

balancing Li;

       a  = c

 balancing Br;

        2b  = c

 let a  = 1;

       c  = 1

        b = \frac{1}{2}  

or a = 2, b = 1 , c = 2

        2Li   +   Br₂  →    2LiBr

        P   +   Cl₂  →    PCl₃

Using the same method;

      aP  + bCl₂ → cPCl₃

balancing P;

          a  = c

balancing Cl;

          2b  = 3c

let a = 1;

     c  = 1

      b  = \frac{3}{2}

 or

  a  = 2, b  = 3, c  = 2

    2P   +   3Cl₂  →    2PCl₃

iii,

   H₂   +   SO₂  →   H₂S   +   H₂O

use coefficients a,b,c and d;

    aH₂   +   bSO₂  →   cH₂S   +   dH₂O

balancing H;

    2a = 2c + 2d

balancing S;

     b  = c

balancing O

    2b  = d

 let b  = 1,

      c = 1

       d  = 2

    a  = 3

    3H₂   +   SO₂  →   H₂S   +   2H₂O

3 0
3 years ago
I don't quite understand it
irina1246 [14]
So, you need to have same ammount of atoms on the left and on the right side of the equation. You need to count the ammount of attoms of every substance on the left, and make sure that on the right side the ammount is same. For example in the 1st one it’s 6Sn+2P4=2Sn3P4, so that you have 6atoms of Sn on the left and 6 atoms of Sn on the right, same with the P
6 0
3 years ago
Calculate the mole fraction of kbr (molar mass 119.00 g/mol) in a solution made by dissolving 0.30 g kbr in 0.400 l of H2O (d =
julia-pushkina [17]

The mole fraction of KBr in the solution is 0.0001

<h3>How to determine the mole of water</h3>

We'll begin by calculating the mass of the water. This can be obtained as follow:

  • Volume of water = 0.4 L = 0.4 × 1000 = 400 mL
  • Density of water = 1 g/mL
  • Mass of water =?

Density = mass / volume

1 = Mass of water / 400

Croiss multiply

Mass of water = 1 × 400

Mass of water = 400 g

Finally, we shall determine the mole of the water

  • Mass of water = 400 g
  • Molar mass of water = 18.02 g/mol
  • Mole of water = ?

Mole = mass / molar mass

Mole of water = 400 / 18.02

Mole of water = 22.2 moles

<h3>How to de terminethe mole of KBr</h3>
  • Mass of KBr = 0.3 g
  • Molar mass of KBr = 119 g/mol
  • Mole of KBr = ?

Mole = mass / molar mass

Mole of KBr = 0.3 / 119

Mole of KBr = 0.0025 mole

<h3>How to determine the mole fraction of KBr</h3>
  • Mole of KBr = 0.0025 mole
  • Mole of water = 22.2 moles
  • Total mole = 0.0025 + 22.2 = 22.2025 moles
  • Mole fraction of KBr =?

Mole fraction = mole / total mole

Mole fraction of KBr = 0.0025 / 22.2025

Mole fraction of KBr = 0.0001

Learn more about mole fraction:

brainly.com/question/2769009

#SPJ1

6 0
2 years ago
ch sulfide (ZnS) occurs in the zinc blende crystal structure, (a) If 254 g of ZnS contains 170 g of Zn, what is the mass ratio o
Aleonysh [2.5K]

Answer:

The mass ratio of zinc to sulfide is 85:42.

2.5559 kg of Zn are in 3.82 kg of ZnS.

Explanation:

a) Mass of zinc sulfide = 254 g

Mass of zinc in a zinc sulfide sample = 170 g

Mass of sulfide in zinc sulfide sample = x

254 g = 170 g+ x

x = 84 g

The mass ratio of zinc to sulfide:

\frac{170 g}{84 g}=\frac{85}{42}

b) Mass of zincsulfide sample = 3.83 kg

The mass ratio of zinc to sulfide is 85:42.

Let the mass of zinc and sulfide be 85x and 42x respectively:

85 x+ 42 x=3.82 kg

x =0.03007 kg

Mass of an zinc= 85x=85 × 0.03007 kg= 2.5559 kg

8 0
3 years ago
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