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<u>Answer:</u> The molality of non-electrolyte is 24.69 m
<u>Explanation:</u>
We are given:
Mole fraction of saturated aqueous solution = 0.310
This means that 0.310 moles of non-electrolyte is present.
Moles of water (solvent) = 1 - 0.310 = 0.690 moles
To calculate the mass from given number of moles, we use the equation:
Moles of water = 0.690 moles
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
To calculate the molality of solution, we use the equation:
Where,
= Moles of solute (non-electrolyte) = 0.310 moles
= Mass of solvent (water) = 12.42 g
Putting values in above equation, we get:
Hence, the molality of non-electrolyte is 24.69 m
The Molarity of the solution is given by:
--- (A)
But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.
Molecular weight of NaCl = 58.44 grams/mole.
So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl
Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre
The correct answer is: 0.741 moles/litre = Molarity
But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.
Molecular weight of NaCl = 58.44 grams/mole.
So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl
Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre
The correct answer is: 0.741 moles/litre = Molarity