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4 years ago

When an RL circuit is connected to a battery, which is true about its initial and final states?

Physics

1 answer:

zubka84 [21]4 years ago

7 0

Answer:A

Explanation:

In R-L circuit current is given by

$i=i_0\left [ 1-e^{\frac{-t}{L/R}}\right ]$

where i=current at any time t

$i_0=maximum\ current$

R=resistance

L=Inductance

at t=0 $e^{\frac{-t}{L/R}}$ approaches to 1

therefore $i=i_0\left [ 1-1\right ]$

i=0

when t approaches to $\infty$ , $e^{\frac{-t}{L/R}}$ approaches to zero

thus $i=i_0$

thus we can say that initially circuit act as broken wire with zero current

and it increases exponentially with time and act as ordinary connecting wire

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Answer:

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Explanation:

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3 years ago

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4 years ago

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3 years ago

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Answer:

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