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KatRina [158]
2 years ago
14

Is constant velocity same as constant acceleration?​

Physics
2 answers:
irakobra [83]2 years ago
7 0

Answer:

No

Explanation:

constant velocity means zero acceleration because acceleration is rate of change of velocity. So when velocity remains constant there would be no acceleration.

in case of constant acceleration it means that velocity changes but with some consistent (same) amount each time. For example some object falling from tower, Velocity of the object will change(increases) by 9.8m/s for each second due to gravity of Earth. In this case there is change in velocity each second but with some consistent amount that is 9.8m/s.

Kamila [148]2 years ago
5 0
No they are very different and are even measured in different units. Velocity is usually defined as “the rate of change of position with respect to time, whereas acceleration is the rate of change of velocity.”
Hope this helps. Have a good day.
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sdas [7]
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5 0
3 years ago
The results of a recent television survey of American TV households revealed that 86 out of every 100 TV households have at leas
Lelechka [254]

Answer:

q = \dfrac{14}{100}

Explanation:

given,

86 out of every 100 TV households have at least one remote control

Probability of any material is calculated by.

Probability = \dfrac{favourable\ outcome}{Total\ outcome}

P(at\ least\ one\ remote\ control)=\dfrac{86}{100}

P(at\ least\ one\ remote\ control)=0.86

now, Calculating probability that at least one remote control

   q = 1 - 0.86

   q = 0.14

P(doesnot\ have\ at\ least\ one\ remote\ control)=\dfrac{14}{100}

q = \dfrac{14}{100}

7 0
3 years ago
What will occur when the waves peak at the same place at the same time?
dedylja [7]
Hello!

This is a matter of superposition.
When the waves peak at the same time and place, they produce constructive interference, meaning the waves interact together in a positive way, to make a wave with Amplitude of both waves added together. When the peaks differ however, at the same time and place, then it is destructive interference and the waves essentially cancel each other out.

Hope this helps. Any questions please just ask. Thank you kindly.
5 0
3 years ago
a man hits a golf ball (0.2kg) which accelerates at a rate of 20 m/s what amount of force acted on the ball
MAVERICK [17]

The ball only accelerates during the brief time that the club is in contact
with it. After it leaves the club face, it takes off at a constant speed.

If it accelerates at 20 m/s² during the hit, then

   Force = (mass) x (acceleration) = (0.2kg) x (20 m/s²) = <em>4 newtons</em> .


8 0
3 years ago
Read 2 more answers
MATHPHYS HELP
rusak2 [61]

Answer:

16.4287

Explanation:

The force and displacement are related by Hooke's law:

F = kΔx

The period of oscillation of a spring/mass system is:

T = 2π√(m/k)

First, find the value of k:

F = kΔx

78 N = k (98 m)

k = 0.796 N/m

Next, find the mass of the unknown weight.

F = kΔx

m (9.8 m/s²) = (0.796 N/m) (67 m)

m = 5.44 kg

Finally, find the period.

T = 2π√(m/k)

T = 2π√(5.44 kg / 0.796 N/m)

T = 16.4287 s

3 0
3 years ago
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