Ask question

Ask question

All categories

3 years ago

11

What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius

?

1 answer:

Tanzania [10]3 years ago

3 0

Answer:

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

M = 312g

ΔT = 15°C

C =?

Q = MCΔT

C = Q/MΔT

C = 6527/(312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C

You might be interested in

2. Soil is made of <br> A. air<br> B. rocks<br> C. decomposed leaves<br> D. all of the above

Irina18 [472]

Answer:

B

Explanation:

<h2>Soil is a mixture of </h2><h2 /><h2>tiny particles of rock,</h2>

<h2>dead plants and animals </h2>

<h2>,air and water.</h2>

3 0

3 years ago

Read 2 more answers

For the chemical reaction

polet [3.4K]

Answer:

806.3g

Explanation:

Given parameters:

Number of moles of silver nitrate = 4.85mol

Unknown:

Mass of silver chromate = ?

Solution:

2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃

To solve this problem, we work from the known to the unknown;

The known specie here is AgNO₃ ;

From the balanced chemical equation;

2 moles of AgNO₃ will produce 1 mole of Ag₂CrO₄

4.85 moles of AgNO₃ will produce $\frac{4.85}{2}$ = 2.43moles of Ag₂CrO₄

Mass of silver chromate produced;

mass = number of moles x molar mass

Molar mass of Ag₂CrO₄

Atomic mass of Ag = 107.9g/mol

Cr = 52g/mol

O = 16g/mol

Input the parameters and solve;

Molar mass = 2(107.9) + 52 + 4(16) = 331.8g/mol

So,

Mass of Ag₂CrO₄ = 2.43 x 331.8 = 806.3g

8 0

2 years ago

A chemical reaction in which compounds break up into simpler constituents is a _______ reaction.

sweet [91]

The awnser to ur question is B

7 0

3 years ago

Read 2 more answers

To which group of alcohols does 3,4-dimethyl-2-pentanol belong?

dsp73

Answer:

The answer is A

Explanation:

8 0

2 years ago

if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?

skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>

Density = mass / volume

The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

<span> = 1246.25 g</span>

Specific heat capacity of water = 4.186 J<span>/ g °C.</span>

Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
T = 1.04 °C + 23 °C
T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.

4 0

3 years ago