<span>Water molecules have a lower
boiling temperature than oxygen molecules, so at room temperature they
exist as a liquid rather than a gas.
hope it helps
</span>
Answer:
- <u><em>294.307 g/mol</em></u>
Explanation:
The first question for this statment is:
- <em>Calculate the gram-formula-mass of aspartame. </em>
<em />
<h2>Solution</h2>
The chemical formula is:
The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:
Atom Number of atoms Atomic mass Total mass
g/mol g/mol
C 14 12.011 14 × 12.011 = 164.154
H 18 1.008 18 × 1.008 = 18.144
N 2 14.007 2 × 14.007 = 28.014
O 5 15.999 5 × 15.999 = 79.995
===================
Total 294.307 g/mol
Answer: 294.307 g/mol
Answer:
Water (H2O) is polar because of the bent shape of the molecule. The shape means most of the negative charge from the oxygen on side of the molecule and the positive charge of the hydrogen atoms is on the other side of the molecule. When solutes are added to water, they may be affected by the charge distribution
Explanation:
The pH of pure water is 7.0, which is neutral.
For a pH below this, the water is acidic. Substances that are acidic are often corrosive and thus could cause weather damaging. The pH of the precipitation in NY is below that of the precipitation in IL, and NY receives more precipitation, so for both of those reasons, it is likely to have more chemical weathering.
<span> </span>
Answer
is: volume is 20 mL.<span>
c</span>₁(CH₃COOH) = 2,5 M.<span>
c</span>₂(CH₃COOH) = 0,5 M.<span>
V</span>₂(CH₃COOH) = 100 mL.<span>
V</span>₁(CH₃COOH) = ?<span>
c</span>₁(CH₃COOH) · V₁(CH₃COOH)
= c₂(CH₃COOH) · V₂(CH₃COOH).<span>
2,5 M · V</span>₁(CH₃COOH)
= 0,5 M · 100 mL.<span>
V</span>₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.<span>
V</span>₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.
