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MrMuchimi
3 years ago
11

What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius

?
Chemistry
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

M = 312g

ΔT = 15°C

C =?

Q = MCΔT

C = Q/MΔT

C = 6527/(312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C

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A gaseous compound has a mass of 8.00 g at 2.81 atm and 300. K in a 1.00 L container.
Maurinko [17]

Answer:

The question asks for moles, which can be obtained from P-V-T data using the ideal gas

equation: n =

RT

PV .

Now use the rearranged gas law to determine the number of moles in the sample:

!

n = PV

RT = (6.47 x 105 Pa)(5.65 x 10-4m3

)

(8.314 J

mol K )(21.7 + 273.15 K) = 0.149 mol.

All conditions except the pressure and volume are fixed, so P1V1 = P2V2 can be used: 3.62 L

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2

1 1

2 = =

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4 years ago
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The chemical name is nickel (III) oxide .
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Write the balanced chemical equation for the Haber-Bosch process, that is, the combination of nitrogen and hydrogen to form ammo
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What is the molar solubility of MgF2 in a 0.36 M Mg(NO3)2 solution? For MgF2, Ksp = 8.4 × 10^–8
Valentin [98]

Answer:

2.4 × 10⁻⁴ M

Explanation:

Step 1: Calculate the concentration of Mg²⁺ coming from Mg(NO₃)₂

Mg(NO₃)₂ is a strong electrolyte and the molar ratio of Mg(NO₃)₂ to Mg²⁺ is 1:1. The initial molar concentration of Mg²⁺ is 1/1 × 0.36 M = 0.36 M.

Step 2: Make an ICE chart for the solution of MgF₂

        MgF₂(s) ⇄ Mg²⁺(aq) + 2 F⁻(aq)

I                           0.36             0

C                           +S             +2S

E                         0.36+S         2S

The solubility product constant is:

Ksp = [Mg²⁺] × [F⁻]² = (0.36+S) × (2S)²

Since S <<< 0.36, 0.36+S ≈ 0.36.

Ksp = 0.36 × 4S² = 8.4 × 10⁻⁸

S = 2.4 × 10⁻⁴ M

7 0
3 years ago
Assertion: Atomic mass of aluminium is 27 Reason: An atom of aluminium is 27 times heavier than 1 / 12th of the mass of the C –
Korvikt [17]

Answer:

i is the correct answer.

Explanation:

the RAM of aluminum is indeed 27. And since the RAM of substances are measured in terms of the C-12 isotope then R indeed explains why the RAM Al is 27.

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