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Dominik [7]
3 years ago
15

Did you detect a difference in the radiation levels between the intact smoke detector and the americium-241 removed from the smo

ke detector? if so why do you think the smoke detector is designed with that difference?
Physics
1 answer:
Triss [41]3 years ago
4 0

Lab results:

Smoke detector = 40.0 cpm Geiger counter

Americium-241 = 10,400 cpm Geiger counter

The great difference in the radiation level means that Americium-241 is more radioactive than the smoke detector itself. Americium-241 is used as a source of alpha radiation. This radiation ionizes the air particles inside the smoke detector allowing it to conduct small amounts of electric current. For example, if smoke particles go inside the smoke detector, these are hit by alpha radiation and thus causing a drop in current. The drop in current is detected by the smoke detector which then sets off the alarm.

You might be interested in
it takes a hose 4 minutes to fill a rectangular aquarium 9 inches long, 13 inces wide, and 14 inces tall. how long will it take
Studentka2010 [4]

Answer: 43.58 min

Explanation:

Knowing the volume of a rectangular object is length x width x height, we have two volumes:

V_{1}=(9 in)(13 in)(14 in)=1638 in^{3}

V_{2}=(21 in)(25 in)(34 in)=17850 in^{3}

And we know it takes a time of 4 minutes to fill V_{1}.

If we want to know how long will it take the same hose to fill another tank with volume V_{2}, we can use the <u>Rule of three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known:

1638in^{3} ---- 4min

17850in^{3} ---- ?

?=\frac{(17850 in^{3})(4min)}{1638 in^{3}}

Finally:

?=43.58 min

4 0
4 years ago
Chewy travels an average of 22 mph, how many hours does it take him to cover a 110 mike course?
anzhelika [568]
That would be 110/22, which is 5 hours
5 0
3 years ago
When does gravitational lensing occur? High concentrations of dark matter cause length contraction of nearby objects. The gravit
Stella [2.4K]

Answer:

A massive object (like a galaxy cluster) bends the light from an object (like a quasar) that lies behind it.

Explanation:

A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.

This technique is useful for astronomers since they make research of faraway objects (at hight redshift) that otherwise will difficult to detect with a telescope.

4 0
4 years ago
A swimmer speeds up from 1.1 m/s to 3.2 m/s during the last 13.0 seconds of the race. What is the acceleration of the swimmer?​
rodikova [14]

Answer:

a = 0.16 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 3.2 [m/s]

Vo = initial velocity = 1.1 [m/s]

t = time = 13 [s]

a = acceleration [m/s²]

Now replacing:

3.2=1.1+a*13\\2.1=13*a\\a=0.16[m/s^{2} ]

7 0
4 years ago
A 16 kg science book is dropped of a 120 meter high cliff. Assuming a closed system:
Lapatulllka [165]

Answer:

Explanation:

The mass of that science book...wow. In pounds that would be 35.2! Yikes!

Anyway, we need final velocity here, and the mass of the book has nothing to do with how fast it falls. Everything is pulled by the same gravity. A feather falls at 9.8 m/s/s and so does an elephant. Mass is useless information. The equation we will use is

v^2=v_0^2+2aΔx  where

v is the final velocity, our unknown,

v₀ is the initial velocity which is 0 since someone had to be holding the book before dropping it,

a is the pull of gravity which is always -9.8 m/s/s, and

Δx = -120 which is the displacement (it's negative because the book falls below the point from which it was dropped). Filling in:

v^2=0^2+2(-9.8)(-120) so

v=\sqrt{2(-9.8)(-120)} and

v = 48 m/s

As far as how far above the bottom of the cliff the object is when it is moving at 12 m/s we will use the same equation, but the velocity will be 12:

12^2=0^2+2(-9.8)Δx and

144 = -19.6Δx so

Δx = -7.3 m. That's how far from the top of the cliff it is. We subtract then t find out how far it is from the bottom:

120 - 7.3 = 112.7 m off the ground.

6 0
3 years ago
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