Answer:
The answer to the question is
The mass of the water in the container, assuming that all the heat lost by the copper is gained by the water is 116.23 grams
Explanation:
To solve this we list out the variables thus,
mass of copper = 110g
specific heat capacity of copper = 0.20 j/C g
Initial temperature of copper = 82.4 C
Final temperature of copper and water = 24.9 C
therefore
From the formula for sensible heat, ΔH = m×c×ΔT
we have, where
H = senced heat,
m = mass,
ΔT = temperature change
110 × 0.20 × (82.4 - 24.9) = mw × 4.186 × (24.9 - 22.3)
1265 J = mw ×10.8836 or mw = 116.23 g
Therefpre the mass of water is 116.23 g
Answer:
If this is multiple choice it would be: 1. Close in size, and 2. They are about the same distance from the sun.. Hopefully these will help.
Answer:
180.845 mol
Explanation:
Molar mass of Ca: 40,078 g/mol
Molar mass of C: 12,0107 g/mol
Molar mass of O: 15,999 g/mol
Molar mass of CaCO3: (40,078+12,0107+3×15,999) 100,0857 g/mol
The number of moles= mass of bag in g ÷ molar mass of CaCO3
⇒ n= (18.1×1000)÷100,0857 = 180.845 mol
Explanation:
1.00 mole of O2 contains 2 × 6.023 × 10²³ atoms
= 12.046 × 10²³
In option A
No of oxygen atoms= 0.667 × 3 × 6.023 × 10²³
= 12.046× 10²³ ✓
In option B
No of oxygen Atoms = 1 × 2 × 6.023 × 10²³
= 12.046 × 10²³ ✓
In option C
No of oxygen atoms= 2 × 6.023 × 10²³
= 12.046 × 10²³ ✓
So option D is correct
the answer will there for be ironic