The mass of water produced by the reaction of the 23 g of
is 13.8 g.
The given chemical reaction;

In the given compound above, we can deduce the following;
- molecular mass of
= 28 + (2 x 16) = 60 g - molecular mass of
= 2(18) = 36 g
60 g of
--------- 36 g of water
23 g of
------------- ? of water

Thus, the mass of water produced by the reaction of the 23 g of
is 13.8 g.
- <em>"Your question is not complete, it seems to be missing the following information";</em>
In the reaction of the given compound,
, what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
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Answer: The statement which could possibly not be true is C -" Liquid X can exist as a stable phase at 25°C, 1atm."
Explanation:
Triple point is the point where a substance co-exist as solid liquid and gas. At any point other than the triple point, the substance exist as a single phase substance.
As shown in the diagram, Liquid cannot exist as a stable phase at 1atm( below the the triple point pressure of 2atm) as the liquid can only exist beyond the pressure of triple point.
8. 4 grams of water will be produced.
The boiling point of a liquid can be raised by adding pressure. Like wise, if you lower the pressure the boiling point goes down. This can be explained by the fact that boiling occurse when the vapor pressure equals the outside pressure so when the outside pressure rises the vapor pressure required for boiling also rises. Vapor pressure is proportional to temperature and therefore temperature needs to increase to make the vapor pressure increase.
I hope this helps. Let me know in the comments if anything is unclear or if you want me to explain anything further.
Answer:
1. 72.9 atm
2. 0.43937 K
Explanation:
1. Gray- lussacs law is p1/t1=p2/t2 so we use this formula to figure it out by filling in the variables and solving
p1=45.0 atm
t1=323 K
p2= ?
t2=523 K
Now we fill in this in the formula and solve - 45.0 atm/ 323 K = p2/ 523 K
and now we solve for p2 by multiplying 535k by each side to give us p2
2. Using the same formula we get 10.0atm/? = 12.0 atm/ 273.15 k and we divide both sides by 10.0 atm