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zimovet [89]
4 years ago
4

Consider the reaction below. 2 upper N subscript 2 upper O subscript 5 (g) double-headed arrow 4 upper N upper O subscript 2 (g)

plus upper o subscript 2 (g).
Chemistry
1 answer:
lubasha [3.4K]4 years ago
6 0

Answer:

The concentrations of the products and reactants do not change.

Explanation:

The following information is missing:

<em>If the reaction is at dynamic equilibrium at 500 K, which statement applies to the given chemical system? </em>

  • <em>The forward and reverse reactions no longer occur. </em>
  • <em>The rates of the forward and reverse reactions are unequal. </em>
  • <em>The concentrations of the products and reactants do not change. </em>
  • <em>The forward reaction stops at 500 K.</em>

Dynamic equilibrium means that the rate of the forward and reverse reactions are equal and different from zero. Then, the concentrations of the products and reactants do not change.

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2H2 + O2 --&gt; 2 H2O<br> +<br> How many moles of oxygen is required to produce 13.3 moles of water?
LenKa [72]

Answer:

Explanation:

Let the number of moles of oxygen = x

2H2 + O2 --> 2 H2O

           x             13.3

Since the balance number for oxygen is 1 and the balance number for water is 2, you must set up a proportion. (Those balance numbers represent the number of moles).

1/x = 2 / 13.3                      Cross Multiply

2*x = 13.3                          Divide both sides by 2

2x/2 = 13.3/2

x = 6.65

You need 6.65 moles of oxygen.

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Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
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