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Answer:
○ People biking have the same right to be on the road as motorists, except for roads (such as expressways) where signs prohibit bikes
Explanation:
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Answer: hello attached below is the properly written chain reaction to your question
answer :
d[NO] / dt = ![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20%2B%20K_%7B3f%7D%5BN%5D%5BOH%5D)
d[N] / dt = ![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20-%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Explanation:
<u>write out expressions for d[NO] / dt and d[N] / dt</u>
Given :
properly written chain reaction ( attached below)
Expression for d[NO] / dt can be written as
![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20%2B%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Expression for d[N] / dt can be written as
![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20-%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Answer:

Explanation:
Given that
P = 4 KPa
Contact angle = 6°
Surface tension = 1 N/m
Lets assume that atmospheric pressure = 100 KPa
Lets take that density of water =
So the capillarity rise h


h= 9.61 m
We know that for capillarity rise h





Answer:

Explanation:
Given that
Shear modulus= G
Sectional area = A
Torsional load,

For the maximum value of internal torque

Therefore

Thus the maximum internal torque will be at x= 0.25 L
![t(x)_{max} = \int_{0}^{0.25L}p sin( \frac{2\pi}{ L} x)dx\\t(x)_{max} =\left [p\times \dfrac{-cos( \frac{2\pi}{ L} x)}{\frac{2\pi}{ L}} \right ]_0^{0.25L}\\t(x)_{max} =\dfrac{p\times L}{2\times \pi}](https://tex.z-dn.net/?f=t%28x%29_%7Bmax%7D%20%3D%20%5Cint_%7B0%7D%5E%7B0.25L%7Dp%20sin%28%20%5Cfrac%7B2%5Cpi%7D%7B%20L%7D%20x%29dx%5C%5Ct%28x%29_%7Bmax%7D%20%3D%5Cleft%20%5Bp%5Ctimes%20%5Cdfrac%7B-cos%28%20%5Cfrac%7B2%5Cpi%7D%7B%20L%7D%20x%29%7D%7B%5Cfrac%7B2%5Cpi%7D%7B%20L%7D%7D%20%20%5Cright%20%5D_0%5E%7B0.25L%7D%5C%5Ct%28x%29_%7Bmax%7D%20%3D%5Cdfrac%7Bp%5Ctimes%20L%7D%7B2%5Ctimes%20%5Cpi%7D)