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3 years ago

Which has a greater density, a pound of feathers or a pound of gold

Chemistry

1 answer:

artcher [175]3 years ago

3 0

Answer:

Explanation:

Hello!!

Please remember that density=mass/volume.

In this case, we have the same mass for the feathers and the gold (1 pound).

So, if the mass is the same for both we have:

Df*Vg=Dg*Vf where f means feathers and g means gold.

In this case we see density is inversely related to volume. Both materials have the same mass. So which one have a bigger volume?

For this take a pound of feathers and submerge in a known volume of water. Note the displacement. Do the same for a pound of gold. Whichever has the smaller displacement, has the greater density.

In this case, Gold has the greatest density.

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A 1. 07 g sample of a noble gas occupies a volume of 363 ml at 35°c and 678 mmhg. Identify the noble gas in this sample. (r = 0.

Margaret [11]

The identity of the noble gas is the sample is Krypton

<h3>Ideal Gas law</h3>

From the question, we are to determine the identity of the noble gas in the sample

From the ideal gas equation, we have that

PV = nRT

∴ n = PV / RT

Where P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

From the given information,

P = 678 mmHg = 0.892105 atm

V = 363 mL = 0.363 L

R = 0.08206 L.atm/mol.K

T = 35 °C = 35 + 273.15 K = 308.15 K

Putting the parameters into the equation, we get

n = (0.892105 × 0.363)/ (0.08206 × 308.15)

n = 0.0128 moles

Now, we will determine the Atomic mass of the sample

Using the formula,

Atomic = Mass / Number of moles

Atomic mass of the substance = 1.07 / 0.0128

Atomic mass of the substance = 83.6 amu

The noble gas with the closest atomic mass to this value is Krypton.

Molar mass of Krypton = 83.798 amu

Hence, the identity of the noble gas is the sample is Krypton

Learn more on Ideal Gas law here: brainly.com/question/20212888

#SPJ12

4 0

2 years ago

0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is: 2Al(OH)3(s) +

Veseljchak [2.6K]

Answer:

The answer to your question is 1.1 moles of water

Explanation:

2Al(OH)₃ + 3H₂SO₄ ⇒ Al₂(SO₄)₃ + 6H₂O

0.45 mol 0.55 mol ?

Process

1.- Calculate the limiting reactant

Theoretical proportion

Al(OH)₃ / H₂SO₄ = 2/3 = 0.667

Experimental proportion

Al(OH)₃ / H₂SO₄ = 0.45 / 0.55 = 0.81

From the proportions, we conclude that the limiting reactant is H₂SO₄

2.- Calculate the moles of H₂O

3 moles of H₂SO₄ ---------------- 6 moles of water

0.55 moles of H₂SO₄ ----------- x

x = (0.55 x 6) / 3

x = 3.3 / 3

x = 1.1 moles of water

5 0

3 years ago

Which bond has the greatest ionic character? A) H-Cl B) H-F c) H-O d) H-N

Len [333]

I really hope that this helps. H-F because the difference in electronegativity is the greatest, about 1.9 on the Pauling scale. The term means which bond has the greatest polarity and is thus most similar to an ionic bond, which involves the transfer of an electron (in opposition to covalent bonds, which share electrons). It is H-F because out of all the atoms here bonded with H, ie hydrogen, F is the most electronegative which means it can pull the bonded electrons to itself more than can Cl, O, and N. <span>That means a stronger polarization of the electron cloud forming the bond with hydrogen and therefore a stronger ionic character.</span>

5 0

3 years ago

What is the density of an object with the density of 3 when cut in half?

anyanavicka [17]

The density is 3 because the density remains the same.

8 0

3 years ago

True or False? The fatal 1930 incident in Muese Valley, Belgium, was associated with leakage of toxic chemicals from a former du

Westkost [7]

Answer:

FALSE

Explanation:

The incident of Muese Valley occured in 1930 due to air pollution.

Muese Valley lies along the river Muese which is situated Huy and Liege, Belgium. This region was crowded with industries including steel manufacturers, glass manufacturers, explosives plants, zinc smelter, etc.

The increase number of industries and population lead to the sources of pollution. Also increase in burning of domestic coal increased pollution surrounding the area.

Air pollution became so severe at this region that people have severe respiratory problems. Residents suffered from vomiting, retrosternal pain, coughing fits and several experienced nausea. There were fog and smog all over and many people died.

Hence the answer is FALSE.

8 0

3 years ago