The option which accurately defines kinetic energy from the choices above is:
the energy an object has because of its motion
The correct answer choice is option c
In order words, kinetic energy is that type of energy which a body or an object posess due to its relative motion.
<h3>What is energy?</h3>
Energy can simply be defined as the capacity of doing work.
Energy is a derived quantity; meaning that it is obtained from the combination of fundamental quantities.
The unit of energy joules.
Other examples of derived quantities just like energy too are:
- Volume
- Speed
- Acceleration
- Density.
- Upthrust
- Momentum
- Momentum
- Power
- Pressure
- Force
Below are some few forms of energy; these are:
- Kinetic energy
- Potential energy
- Mechanical energy
- Solar energy
- Light energy
- Chemical energy
So therefore, the option which accurately defines kinetic energy from the choices above is:
the energy an object has because of its motion
Learn more about energy:
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Completely natural process with almost no harmful side effects
Question 17
The subscript 2 is the atomic number for helium and subscript 4 is the mass number for Helium
<u><em>explanation</em></u>
when writing down an isotope of an element the mass number of that isotope is written in upper side of the chemical symbol, while atomic number is written on the lower side.
Since 4 is on upper side it is the mass number of He, while 2 is the atomic number since it is on lower side.
Question 18
The type of radiation emitted when polonium -212 form lead 208 is an alpha particle
<u><em>explanation</em></u>
Alpha decay is a decay in which an atomic nuclei emit an alpha particles and be transformed into different atomic nuclei with a mass number that is reduced by 4
polonium 212 is reduced by 4 to form lead 208 therefore it undergo alpha particle decay.
Answer:
pH = 9.475
Explanation:
Hello there!
In this case, according to the basic ionization of the hydroxylamine:

The resulting equilibrium expression would be:
![Kb=\frac{[HONH_3^+][OH^-]}{[HONH_2]} =1.1x10^{-8}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BHONH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BHONH_2%5D%7D%20%3D1.1x10%5E%7B-8%7D)
Thus, we first need to compute the initial concentration of this base by considering its molar mass (33.03 g/mol):
![[HONH_2]_0=\frac{1.34g/(33.03g/mol)}{0.500L} =0.0811M](https://tex.z-dn.net/?f=%5BHONH_2%5D_0%3D%5Cfrac%7B1.34g%2F%2833.03g%2Fmol%29%7D%7B0.500L%7D%20%3D0.0811M)
Now, we introduce
as the reaction extent which provides the concentration of the hydroxyl ions to subsequently compute the pOH:

However, since Kb<<<<1, it is possible to solve for
by easily neglecting it on the bottom to obtain:
![x=[OH^-]=\sqrt{1.1x10^{-8}*0.0811}= 2.99x10^{-5}](https://tex.z-dn.net/?f=x%3D%5BOH%5E-%5D%3D%5Csqrt%7B1.1x10%5E%7B-8%7D%2A0.0811%7D%3D%202.99x10%5E%7B-5%7D)
Thus, the pOH is:

And the pH:

Regards!