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Rzqust [24]
4 years ago
10

Help this question is super hard!!

Chemistry
2 answers:
4vir4ik [10]4 years ago
6 0

Answer:

All of them can but h2o will be the weakest because the bonds in it are very weak and it has a low base/acid value

melomori [17]4 years ago
4 0

Answer:

They all can, but  HCl would be the strongest conductors because they are strong acids/bases, meaning their ions dissociate at a faster rate in aqueous solution.

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Need help ASAP!!!!!!!
geniusboy [140]
My Heroes is the time of my time I am in college now that I will do it again tomorrow night and you can do something to me about it and then I will never go back again I hope that I can do this again I don’t want
8 0
3 years ago
One mole of ar initially at 305 k undergoes an adiabatic expansion against a pressure pexternal = 0 from a volume of 8.5 l to a
PilotLPTM [1.2K]
An adiabatic process is when the system is insulated that no heat is released to the surroundings. For this type of process, we have a derived formula written below:

(T₂/T₁)^C = (V₁/V₂)
where C = Cv/nR

From the complete problem shown in the attached picture, Cv = (3/2)R. Thus,
C= (3/2)/1 mol = 3/2

(T₂/305 K)^(3/2) = (8.5 L/82 L)
Solving for T₂,
<em>T₂ = 67.3 K</em>

3 0
3 years ago
What is the difference between elimination and substitution reaction
jasenka [17]

Answer:

a) E2

b) SN2

c) SN2

Explanation:

A substitution reaction involves replacement of an atom or group in a molecule by another atom or group. An elimination reaction is the loss of two atoms from the same molecule leading to the formation of a multiple bond in the molecule.

We must note that primary alkyl halides never undergo SN1/E1 reactions. However, the presence of a strong bulky base such as tert BuO- , E2 reactions predominate. In the presence of strong bases such as OH^- and good nucleophiles such as I^-, SN2 mechanism predominates.

7 0
3 years ago
Structure of 4-isopropyl-2,4,5-triethylheptane
SIZIF [17.4K]

Answer:

See the attached file

Explanation:

4 0
3 years ago
Hydrogen gas and solid gold(III) sulfide are reacted. Pure solid gold metal is formed and gaseous hydrogen sulfide is released.
alexdok [17]

The reactants of the reaction will be solid gold (III) sulfide and hydrogen gas, while the products will be pure solid gold and hydrogen sulfide gas.

<h3>Chemical reactions</h3>

Reactants react together during reactions to arrive at products.

In this case, solid gold (III) sulfide and hydrogen gas react according to the following equation:

Au_2S_3(s) + 3 H_2 (g)-- > 2 Au(s) + 3H_2S(g)

Reactants = solid gold (III) sulfide, hydrogen gas

Products: pure solid gold, hydrogen sulfide gas

More on chemical reactions can be found here: brainly.com/question/1689737

8 0
2 years ago
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