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Lunna [17]
3 years ago
7

Which type of wave interaction is shown in the diagram?

Physics
1 answer:
masya89 [10]3 years ago
5 0

Answer: Constructive interference

Explanation: Just took the test

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Sand on a beach is covered by other layers of sand over time. The extra layers compress the first layer, packing it tighter and
klio [65]
Sandstone can be classified as sedimentary rock. Hope this helps :) If you have any more questions I'm happy to try and help.
3 0
4 years ago
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Goryan [66]

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4 0
3 years ago
Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a co
Igoryamba

Answer:

a. before

Explanation:

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?

from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .

displacement is distance in a specific direction.

before the displacement was maximum at 2mm was instant at time=0.04s.

But later was constant at 0.06s at a displacement point of 1mm

4 0
4 years ago
A kitten has a mass of 0.8 kg. It is moving forward with a momentum of 0.5 kg • m/s. What is the kitten’s velocity?
morpeh [17]

The kitten's velocity is   V=0.625 m/s

<u>Explanation:</u>

<u>Solving the problem,</u>

Given

Mass=0.8 kg

Momentum=0.5 kg.m/s

Velocity=?

We have the formula,

P=M*V

V=P/M

V=0.5 kg.m/s/0.8 kg

V=0.625 m/s

The kitten's velocity is   V=0.625 m/s

<u />

5 0
4 years ago
Two particles, one with charge -6.29 × 10^-6 C and one with charge 5.23 × 10^-6 C, are 0.0359 meters apart. What is the magnitud
navik [9.2K]

Answer:

Force, F = −229.72 N

Explanation:

Given that,

First charge particle, q_1=-6.29\times 10^{-6}\ C

Second charged particle, q_2=5.23\times 10^{-6}\ C

Distance between charges, d = 0.0359 m

The electric force between the two charged particles is given by :

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{-6.29\times 10^{-6}\times 5.23\times 10^{-6}}{(0.0359)^2}

F = −229.72 N

So, the magnitude of force that one particle exerts on the other is 229.72 N. Hence, this is the required solution.

4 0
3 years ago
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