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katrin [286]
4 years ago
6

An object is placed 100 cm in front of a diverging lens of focal length -25cm. A converging lens of focal length 33 1/3 cm is pl

aced 30 cm past the first lens. What is the lateral magnification of this system of lenses?
Physics
1 answer:
bagirrra123 [75]4 years ago
8 0
We use 1/o + 1/i = 1/f  where o is the distance of the object, i as distance of the image and f is the focal length.
Substituting, <span>1/ 100 + 1 / i = - 1 /25 </span>
<span>i = - 20 cm </span>

<span>For the case of the problem,</span>

<span>o = (20 + 30)  = 50 cm </span>

<span>f = 33.33. </span>Using 1<span> / i + 1 / o = 1/f , </span><span> </span><span>i = 100 cm </span>

<span>M = magnification = - i / o </span>

<span>m1 = -(-20)/100 = 20/100 = 0.2 </span>

<span>m2 = -100/50 = -2 </span>

<span>M = m1*m2 = -2 x 0.2 = -0.4.</span>
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coasting down hill on a bicycle

Explanation:

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Potential energy is the energy due to the position of a body. It can be derived using;

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m is the mass

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Now, at the top of the hill, the potential energy is at the maximum. As the bicycle coasts down the potential energy is converted to kinetic energy.  

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