Answer:
1 g
Explanation:
The half-life of Am-242 (16 h) is the time it takes for half of it to disappear.
We can make a table of the mass left after each half-life.
The mass remaining after 48 h is 1 g.
Please I need help with questions 1-4 and can you check if I plot it correct in to the punnet square for questions 1-4 and I nee
d help with determining the percent of homozygous dominant, homozygous recessive and heterozygous for each questions from 1-4 and I need help determining the genotypes and phenotypes for each questions from 1-4 and it’s very hard and I’m struggling with it and if you need to see the picture big then click on it and it will be big
1 answer:
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Answer: -
0.1 ml of bleach should be added to each liter of test solution.
Explanation:-
Let the volume of bleach to be added is B ml.
Density of stock solution = 1.0 g/ml
Mass of stock solution = Volume of stock x density of stock
= B ml x 1.0 g/ml
= B g
Amount of NaOCl in this stock solution = 5% of B g
= x B g
= 0.05 B g
Now each test solution must be added 5 mg/l NaOCl.
Thus each liter of test solution must have 5 mg.
Thus 0.05 B g = 5 mg
= 0.005 g
B =
= 0.1
Thus 0.1 ml of bleach should be added to each liter of test solution.