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photoshop1234 [79]
3 years ago
13

An astronaut takes an iPod onto the space shuttle. An identical iPod remains on Earth. Which statement about the pull of Earth's

gravity on the iPods is true?

Physics
2 answers:
maria [59]3 years ago
5 0
The answer is actually B 
puteri [66]3 years ago
3 0

Answer:

B is the answer because if you throw a phone in space it will hit the ground way slower than if you threw it on earth.

earth pulls the phone back down faster because the earth's gravity is stronger!

Explanation:

The answer can't be A because you have less gravity in space.

C is incorrect because earth's gravity forces us down, but in space you can float

D is incorrect for the same reason as A

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A solution which has a solid solute is saturated at 25°C. It is then heated to 35°C. There is no change in the appearance of the
vampirchik [111]

Answer:

C. oversaturated

Explanation:

Sana nakatulong

8 0
2 years ago
A gorilla weighs 8.00x10^2N and swings from vine to vine. As the gorilla grads a new vine, both vines make an angle of 30 degree
Yakvenalex [24]

Answer:

461.88 N  

Explanation:

Let tension in each vine be T .

The vertical component of this tension of both the vine will add up and balance the weight .

2T cos 30 = mg

2 T x cos 30 = 800

T  = 800 / (2 x cos30 )

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6 0
2 years ago
How can neptune have more mass than uranus but a smaller diameter?
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Neptunes' average density is larger than that of Uranus. Hope this helps!
5 0
2 years ago
A pulse can be described as a single wave disturbance that moves through a medium. Consider a pulse that is defined at time t =
Anastaziya [24]

Answer:

a)A= 3 m

b)y(x)=\dfrac{6}{(x-3t)^2+2}\ m

c)D= 15 m

Explanation:

Given that

y(x)=\dfrac{6}{x^2+2}\ m

v= 3 m/s

a)

The amplitude(A) of the pulse :

When x= 0 ,Then y = A

Put x= 0  

y(x)=\dfrac{6}{x^2+2}\ m

y(0)=\dfrac{6}{0^2+2}\ m

y= A= 3 m

A= 3 m

b)

Distance travel in time t  

x= vt

x= 3 t

y(x)=\dfrac{6}{(x-3t)^2+2}\ m

c)

The distance covered by pulse in the time 5 s

D = v t

D= 3 x 5  

D= 15 m

7 0
3 years ago
A runner achieves a velocity of 12.1 m/s 8.2 sec after he begins. What is
Karo-lina-s [1.5K]

<u>Given</u><u> </u><u>-</u><u> </u>

  • Velocity (v) = 12.1 m/s
  • Time (t) = 8.2 sec

<u>To</u><u> </u><u>find</u><u> </u><u>-</u>

  • Acceleration

<u>Solu</u><u>tion</u><u> </u><u>-</u><u> </u>

★ Acceleration = velocity/ time

→ A = 12.1/8.2

→ 1.47.... m/s²

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>accele</u><u>ration</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>runner</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>1</u><u>.</u><u>4</u><u>7</u><u> </u><u>m</u><u>/</u><u>s²</u><u>.</u>

7 0
3 years ago
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