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2 years ago

Mention one life application on density

1 answer:

5 0

One well-known application of density is determining whether or not an object will float on water. If the object's density is less than the density of water, it will float; if its density is less than that of water, it will sink.In fact, submarines dive below the surface of the water by emptying their ballast tanks

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Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t

stepan [7]

We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
$F=ma$
where $F=-50 N$ is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
$a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2$

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
$a= \frac{v_f^2-v_i^2}{2d}$
where
$v_f=0$ is the final speed of the sled
$v_i=5 m/s$ is the initial speed
$d$ is the distance covered

By rearranging the equation, we find d:
$d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m$

3 0

3 years ago

What will happen to the wavelength of light uf the frequency is doubled?What will happen to the wavelength of light uf the frequ

otez555 [7]

Answer:

if the frequency is double, the wavelength is only half as long

Explanation:

6 0

3 years ago

A ski tow operates on a slope of angle 15.6 ∘ of length 340 m . The rope moves at a speed of 12.7 km/h and provides power for 53

GREYUIT [131]

Answer:

P = 34034.2 Watt

Explanation:

As we know that the slope angle is given as

$\theta = 15.6^0$

now the weight of the rider along the slope is given as

$W = mgsin\theta$

$W = 69(9.81)sin15.6$

$W = 182 N$

now total weight of all 53 riders along the slope is given as

$F = 53 W$

$F = 9647.5 N$

now the speed of the rope is given as

$v = 12.7 km/h = 3.53 m/s$

now the power required is given as

$P = F.v$

$P = 9647.5(3.53)$

$P = 34034.2 Watt$

3 0

3 years ago

How does a gas do work?

Triss [41]

Your answer would be C, "By conserving energy"! A gas can do work through something called the First Law of Thermodynamics. Heat that energy used by the gas during this "work" cannot be created or destroyed however it can be transferred and converted. This energy can only be stored during these processes, not removed. An example of this would be gas in a cylindrical object such as a piston. When the gas is heated, it expands and moves the piston upwards. When it expands, it stores that energy it gains through the heat given.

I hope this helps! (:

8 0

3 years ago

Read 2 more answers

A hot-air balloon consists of a basket hanging beneath a large envelope filled with hot air. A typical hot-air balloon has a tot

Deffense [45]

Answer:

1.05045 kg/m³

Explanation:

$\rho_a$ = Density of air = 1.26 kg/m³

$\rho_{ha}$ = Density of hot air

$m_a$ = Mass of balloon = 539 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Volume of air in balloon = $2.62\times 10^3\ m^3$

The net force on the balloon will be

$F_n=(\rho_a-\rho_{ha})vg$

Also

$F_n=m_ag$

$\\\Rightarrow 549g=(\rho_a-\rho_{ha})vg\\\Rightarrow 549=(1.26-\rho_{ha})2.62\times 10^3\\\Rightarrow -\rho_{ha}=\frac{549}{2.62\times 10^3}-1.26\\\Rightarrow \rho_{ha}=1.05045\ kg/m^3$

The density of hot air inside the envelope is 1.05045 kg/m³

4 0

3 years ago

Mention one life application on density ​

Mention one life application on density