Answer:
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Answer: 590 MW
Water flows over a section of Niagara Falls at the rate of 1.2 × 106 kg/s and falls 50 m. How much power is generated by the falling water? = 5.9 × 108 W = 590 MW , where 'MW' represents megawatts.
Explanation:
Explanation:
Given that,
A hockey puck moves 28 m southward then 14 m northward and finally 4 m southward distance.
The total path covered is called distance and the shortest path covered is called displacement.
Distance = 28 m + 14 m + 4 m
Distance = 46 m
Let the nothward direction is positive y axis and southward direction is negative y axis.
Displacement is equal to the difference of final position and the initial position.
Displacement =-28 m - (-4 m)
= -24 m
The magnitude of displacement is in south direction.
Answer:
1.89*10^8 J
Explanation:
The coefficient of performance of this device is 
where Q .is the useful heat supplied or removed by the considered system and W is the work required by the considered system.
Step 1
Coeffiecient of perfromance for cooling (COPC) = 1.75 = .
Q = 1.75W
Step 2
We convert day into seconds:
1 day = 24 hrs = 86400 seconds
Step 3
Heat that can be extracted from the house in a day is:
Q = 1.75 * 1.25 * 10^3 * 86400 = 189000000 = 1.89*10^8 J
