The most possible cause of 35% increase in time measured is due to the acceleration due to gravity which is 70% less than 9.80 m/s² at this location.
Explanation:
We know that for a linear motion
S=ut+(1/2)*a*t²
Where S= Distance covered
u= initial velocity
t=time period
a= acceleration due to gravity
Since the body is falling vertically downwards "a" is to be replaced by "g"
Moreover, The body is falling from rest "u"=0
Hence the equation reduces to S=1/2*g*t²
t²=2S/g
Since the "g" is in denominator thus a decreased value of "g" would mean increased period. Thus an increase of 35% in the period would translate to a 70% decrease in "g".
Displacement is the area under the velocity/time graph. So for example this object's displacement in the first 3 seconds is (1/2)(3sec)(12.5 m/s)= 18.75m. (and then it starts backing up, displacement decreasing, after 3sec when velocity is negative).
But This object is never speeding up. Its velocity is smoothly decreasing at (25/6) m/s^2 (the slope of the graph). So the answer to the question is actually zero.
The velocity of the submarine immediately after firing the missile is 0.0104 m/s
Explanation:
Mass of the submarine M=50 tonne=
Mass of the missile m=40 kg
velocity of the missile v= 13m/s
we have to calculate the velocity of the submarine after firing
This is the recoil velocity and its expression is derived from the law of conservation of momentum
recoil velocity of the submarine
Explanation:
Given that,
Mass of the car, m = 710 kg
Speed of the car, v = 23 m/s
Drag force, F = 500 N
(a) Let P is the power is required from the car's engine to drive the car on the level ground. Power is given by :
(b) Let P is the power is required from the car's engine to drive the car on up a hill with a slope of 2 degrees.
At this slope, force will be,
Total force will be :
Power is given by :
or
P = 17 kW