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cricket20 [7]
3 years ago
10

11. A man lifts a weight of 300 N through a

Physics
1 answer:
satela [25.4K]3 years ago
7 0

Explanation:

Weight=force=300N

height=2m

time=6seconds

power=?

now,

power (p)=f×h÷t

power=300×2÷6

power=100w

therefore,A man develops 100 watt power in 6 seconds.

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An ideal gas is compressed at constant pressure p=1500 Pa from a volume Vi=0.4 m3 to Vf=0.25 m3. At the same time, heat is trans
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To solve this problem we will apply the first law of thermodynamics and we will make a balance between the heat transferred, its internal energy and the total work. Recall that for gases the definition of work can be expressed in terms of its pressure and volume. Let's start

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Here,

dU = Internal Energy

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But internal energy is unchanged, then

dQ = dW

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Finally, the expression of the heat transferred can be expressed in terms of pressure and volume, so it would end up becoming

dQ = p(v_i-v_f)

Replacing,

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4 years ago
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4 years ago
In the graph below, why does the graph stop increasing after 30 seconds?
stepladder [879]

Answer:

The answer is "Option C".

Explanation:

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6 0
3 years ago
7. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The oncoming water stream has
NNADVOKAT [17]

Answer:

The magnitude of the average force exerted on the water by the blade is 960 N.

Explanation:

Given that,

The mass of water per second that strikes the blade is, \dfrac{m}{t}=30\ kg/s

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Final speed of the outgoing water stream, v = -16 m/s

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F=\dfrac{\Delta P}{\Delta t}

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4 years ago
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