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11Alexandr11 [23.1K]
3 years ago
6

For each molecule of glucose processed during glycolysis, the net yield is ____.

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
3 0
(Starch) I hope this helps you please check again i'am not sure of my answer
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Which of the following gas samples would contain the same amount of gas as 200 mL of helium, He(g), at 25° C and 1 atm?
monitta

Answer:

200\; \rm mL of neon \rm Ne\, (g) at 25^{\circ} \rm C and 1\; \rm atm (the second choice) would contain an equal number of gas particles as 200\; \rm mL\! of \rm He \, (g) at 25^{\circ} \rm C\! and 1\; \rm atm\! (assuming that all four gas samples behave like ideal gases.)

Explanation:

By Avogadro's Law, if the temperature and pressure of two ideal gases is the same, the number of gas particles in each gas would be proportional to the volume of that gas.

All four gas samples in this question share the same temperature and pressure. Hence, if all these gases are ideal gases, the number of gas particles in each sample would be proportional to the volume of that sample. Two of these samples would contain the same number of gas particles if and only if the volume of the two samples is equal to one another.

The second choice, 200\; \rm mL of neon \rm Ne\, (g) at 25^{\circ} \rm C and 1\; \rm atm, is the only choice where the volume of the sample is also 200\; \rm mL \!. Hence, that choice would be the only one with as many gas particles as 200\; \rm mL\! of \rm He \, (g) at 25^{\circ} \rm C\! and 1\; \rm atm\!.

7 0
2 years ago
In ionic bonding, atoms__.
Nutka1998 [239]
In ionic bonding, atoms SHARE ELECTRONS
8 0
2 years ago
What are green boxes on periodic tables
finlep [7]

Answer:

The basic metal ones?

Explanation:

...

3 0
2 years ago
Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =
BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

CaCO₃, Ksp = 8.7 × 10⁻⁹

Answer : The solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

Explanation :

As we know that CaCO₃ dissociates to give Ca^{2+} ion and CO_3^{2-} ion.

The solubility equilibrium reaction will be:

CaCO_3\rightleftharpoons Ca^{2+}+CO_3^{2-}

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][CO_3^{2-}]

Let solubility of CaCO₃ be, 's'

K_{sp}=(s)\times (s)

K_{sp}=s^2

8.7\times 10^{-9}=s^2

s=9.33\times 10^{-5}mol/L

Therefore, the solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

4 0
2 years ago
Heat of vaporization is the amount of heat required to
deff fn [24]
I believe the answer would be c?? I’m not too sure though
5 0
2 years ago
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