Answer:
The magnitude of the electric field is 129375 N/C toward south.
Explanation:
Given that,
Electric force 
(A). We need to calculate the magnitude of the electric field
Using formula of electric field
Where, q = charge of proton
E = electric field
(B). The direction of the electric field is toward the direction of the force.
So, The direction of the electric field is toward south
Hence, The magnitude of the electric field is 129375 N/C toward south.
Officials in the House of Representives have are able to serve a 2 year term and there are no limits as to how many terms.
Answer:
8
Explanation:
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We need first to use the formula F=m(a+g), m iis the total mass, a is the acceleration, g is gravity pulling the blocks. So the procedure will be
<span>m=2kg(both blocks)+500g(both ropes) → m=2.5kg </span>
<span>a=3.00m/s^2 </span>
<span>g=9.8m/s^2 </span>
<span>F=m(a+g) → F=2.5kg (3.00m/s^2 + 9.8m/s^2) → F=2.5kg (12.8m/s^2) → F=32 N
To calculate the tension at the top of rope 1 you need to use the formula </span>T=m(a+g) so it will be <span>T=m(a+g) → T=1.5kg(12.8m/s^2) → T=19.2N
</span>We can now calculate the tension at the bottom of rope 1 using the formula: <span>T=m(a+g) → T=1.25kg(12.8m/s^2) → T=16N
</span>Now to find the tension at the top of rope 2 we do it like this:
<span>T=m(a+g) → T=.25kg(12.8m/s^2) → T=3.2</span>
Free fall condition : acceleration is constant downward and equals to gravitational acc.(g)
because velocity has opposite direction to acceleration, velocity will decrease as it rises.
