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photoshop1234 [79]

3 years ago

9

He does whatever a spider can. Spider-Man, who has a mass of 76 [kg], is clinging onto an inclined wall forming an inclination a

ngle of θ = 50° from the vertical. He exerts a force perpendicular to the inclined wall. What is the magnitude of the force he exerts on the wall? Use g = 9.80 m/s^2

1 answer:

Aliun [14]3 years ago

4 0

Answer:570.54 N

Explanation:

Given

mass of man=76 kg

$\theta =50^{\circ}$

As man is standing over inclined building therefore

its weight has two components i.e. sin and cos component

Force perpendicular to inclined wall

$F=mgcos\theta =76\times 9.8\times \sin 50$

F=570.54 N

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3 years ago

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fiasKO [112]

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From the question we are told that

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The rotational speed of the flywheel is $w = 5,200 \ rev/min = 5200 * \frac{2 \pi }{60} =544.61 \ rad/sec$

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substituting the value

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3 0

3 years ago