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Tems11 [23]
4 years ago
11

Determine the potential difference between two charged parallel plates that are 0.10 cm apart and have an electric field strengt

h of 12 V/cm. V
Physics
1 answer:
NikAS [45]4 years ago
5 0
Formula for Electric Field strength , E =  V/d

where V = Voltage in volts, and d = distance of separation in meters.

d = 0.1 cm ,    E = 12 V/cm

E = V/d =  15 / 0.025

V = E*d

V = 12 * 0.1 = 1.2

Potential difference, V = 1.2 V 
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4 years ago
A weight of 50.0 N is suspended from a spring that has a force constant of 210 N/m. The system is undamped and is subjected to a
Fittoniya [83]

Answer:

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Explanation:

Given that,

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We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :

F=mA\omega^2 .....(1)

A is amplitude

m is mass,

m=\dfrac{W}{g}\\\\m=\dfrac{50}{10}\\\\m=5\ kg

\omega is angular frequency

Angular frequency is given by :

\omega=2\pi f\\\\\omega=2\pi \times 11.5\\\\\omega=72.25\ rad/s

Equation (1) becomes :

F=5\times 0.04\times 72.25^2\\\\F=1044.01\ N

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4 years ago
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Answer:

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