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storchak [24]
3 years ago
6

If a car is moving on a highway at 70 km/hr, going South and then turns to travel 70 km/hr East. What happens to the cars speed

and velocity?
(A)Speed - changing, Velocity - constant


(B)Speed - constant, Velocity - changing


(C)Speed - constant, Velocity - constant


(D)Speed - changing, Velocity - changing
Physics
1 answer:
frozen [14]3 years ago
6 0

Answer:

(B)Speed - constant, Velocity - changing

Explanation:

The magnitude of the velocity ( speed ) has not changed as car is traveling constantly at 70 km/h. But we know the velocity is also having a direction component, and the car which was traveling South is now traveling East. As direction is changed, velocity is changed but as magnitude of velocity has not changed, the speed remain unchanged.

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Sam stands on a 20 m high cliff and throws a 45 g rock with an initial velocity of 5 m/s [forward] to the water below. Use the c
storchak [24]

Answer:

v = 12.52 [m/s]

Explanation:

To solve this problem we must use the energy conservation theorem. Which tells us that potential energy is transformed into kinetic energy or vice versa. This is more clearly as the potential energy decreases the kinetic energy increases.

Ep = Ek

where:

Ep = potential energy [J] (units of joules]

Ek = kinetic energy [J]

Ep = m*g*h

where:

m = mass of the rock = 45 [g] = 0.045 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = (20 - 12) = 8 [m]

Ek = 0.5*m*v²

where:

v = velocity [m/s]

The reference level of potential energy is taken as the ground level, at this level the potential energy is zero, i.e. all potential energy has been transformed into kinetic energy. In such a way that when the Rock has fallen 12 [m] it is located 8 [m] from the ground level.

m*g*h = 0.5*m*v²

v² = (g*h)/0.5

v = √(9.81*8)/0.5

v = 12.52 [m/s]

5 0
2 years ago
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so
gizmo_the_mogwai [7]

Answer:reactant,active site,enzyme below,substrate,products

Explanation:

5 0
2 years ago
Question 7 of 10 A permanent magnet picks up an iron nail, magnetizing the nail. How is this system different from an electromag
Nookie1986 [14]

Answer: I think it’s D i really hope this helps!!!!

Explanation:

5 0
3 years ago
Assume: The bullet penetrates into the block and stops due to its friction with the block. The compound system of the block plus
tino4ka555 [31]

Answer:

1)4.7334J

2)225.4m/s

Explanation:

v= the Velocity of both the bullet and the block after collision=?

H= Height of the bullet along circular arc= 10cm=0.1m

g= acceleration due to gravity= 9.81m/s^2

R= Radius of the circular arc= 18cm= 0.18m

m= Mass of the bullet= 30g= 0.03kg

M= Mass of the block = 4.8 kg

Using the law of conservation of energy

Potential energy of the system= Kinectic energy of the system

1/2 mv^2= mgh..............eqn(1)

But we have two mass m and M

We can write eqn(1) as

0.5(m+M)v^2= (m+M)gh ...........eqn(2)

If we make "v" subject of the formula we have

v = √2gh

Then substitute the values we have

= √2 x 9.81 x 0.1 = 1.40m/s

1) We can now calculate the total energy of the system after collision as

KE = 1/2(m+M)v^2

= 1/2 x (0.03+4.8) x (1.40)^2

KE = 4.7334J

Hence, the total energy of the composite system at any time after the collision is 4.7334J

2)to determine the initial velocity of the bullet.

From law of momentum conservation, which can be expressed as

m1u1+m2u2=(m1+m2)v

Where the initial Velocity of the bullet u1= ?

Final velocity of the bullet = 0

the Velocity of both the bullet and the block after collision=v= 1.40m/s

(0.03×u1) +(u×0)= (4.8+0.03)1.4

0.03u1=6.762

U1=225.4m/s

Hence, the initial velocity of the bullet is 225.4m/s

3 0
2 years ago
Select the correct answer.
aleksklad [387]
A. Alternating current
4 0
2 years ago
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