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marshall27 [118]

3 years ago

14

In carbon monoxide, CO, the mass ratio is 1.00 g of carbon for every 1.33 g of oxygen. How many grams of oxygen will be combined

with 1.00 g of carbon in carbon dioxide, CO2?

1 answer:

notsponge [240]3 years ago

8 0

Answer : The mass of oxygen combined with 1.00 g of carbon in carbon dioxide will be, 2.66 grams.

Explanation :

Law of multiple proportion : It states that when two elements can combine to form two or more different compounds then the mass of one element compared to fixed mass of the other will always be in a ratio of small whole numbers.

As we are given that the mass of ratio of carbon and oxygen in CO is 1 gram and 1.33 gram.

Ratio of C and O in CO = 1 : 1

Ratio of C and O in CO₂ = 1 : 2

So, the mass of ratio of carbon and oxygen in CO₂ will be 1 gram and (2×1.33) 2.66 gram.

Thus, the mass of oxygen combined with 1.00 g of carbon in carbon dioxide will be, 2.66 grams.

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Determine the formulas for these ionic compounds. copper(I) bromide: copper(I) oxide: copper(II) bromide: copper(II) oxide: iron

joja [24]

Answer:

copper(I) bromide: CuBr

copper(I) oxide: Cu₂O

copper(II) bromide: CuBr₂

copper(II) oxide: CuO

iron(III) bromide: FeBr₃

iron(III) oxide: Fe₂O₃

lead(IV) bromide: PbBr₄

lead(IV) oxide: PbO₂

I hope this helped you! Brainliest would be greatly appreciated.

4 0

3 years ago

Find the equilibrium value of [CO] if Kc=14.5 : CO (g) + 2H2 (g) ↔ CH3OH (g) Equilibrium concentrations: [H2] = 0.322 M and [CH3

Annette [7]

Answer:

The equilibrium value of [CO] is 1.04 M

Explanation:

Chemical equilibrium is the state to which a spontaneously evolving chemical system, in which a reversible chemical reaction takes place. When this situation is reached, it is observed that the concentrations of substances, both reagents and reaction products, they remain constant over time. That is, the rate of reaction of reagents to products is the same as that of products to reagents.

Reagent concentrations and products in equilibrium are related by the equilibrium constant Kc. Being:

aA + bB ⇔ cC + dD

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Then this constant Kces equals the multiplication of the concentrations of the products raised to their stoichiometric coefficients between the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

In this case:

$Kc=\frac{[CH_{3}OH ]}{[CO]*[H_{2} ]^{2} }$

You know:

Kc= 14.5
[H₂]= 0.322 M
[CH₃OH] =1.56 M

Replacing:

$14.5=\frac{1.56}{[CO]*0.322^{2} }$

Solving:

$[CO]=\frac{1.56}{14.5*0.322^{2} }$

[CO]= 1.04 M

The equilibrium value of [CO] is 1.04 M

8 0

3 years ago

How have chemists changed our daily lives the most

sladkih [1.3K]

By using what they know to produce new and helpful products

4 0

3 years ago

Which statement best describes the pH of pure water? It is neutral because the concentration of hydronium ions equals that of hy

stira [4]

The pH of pure water has been best described as neutral pH with equal hydronium and hydroxide ions. Thus, option A is correct.

pH has been described as the measurement of hydrogen ions in a solution. The pH has been measured on a scale of 1-14. pH 7 has been the neutral pH.

The higher hydronium ion concentration tends to move the pH from 7 towards 1. The higher hydroxide ion concentration tends to move the pH above 7.

The neutral pH has been neither acidic nor basic with the equal constituents of hydronium and hydroxide ion in the solution.

Thus, the pH of pure water has been 7. It has neutral pH with equal hydronium and hydroxide ions. Thus, option A is correct.

For more information about the pH of the solution, refer to the link:

brainly.com/question/4975103

4 0

2 years ago

Read 2 more answers

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago