A common rule of thumb for controller discretization is to have "6 samples per rise time" in order to achieve a reasonable appro
ximation of the CT controller, without wasting computing resources. Derive the effect on PM that this choice will have. Also derive the relationship of this choice to the effective Nyquist rate for the closed-loop system.
1 answer:
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Answer:
V = 0.5 m/s
Explanation:
given data:
width of channel = 4 m
depth of channel = 2 m
mass flow rate = 4000 kg/s = 4 m3/s
we know that mass flow rate is given as
Putting all the value to get the velocity of the flow
V = 0.5 m/s
Answer:
(a) the cutting time to complete the facing operation = 11.667mins
b) the cutting speeds and metal removal rates at the beginning= 12.89in³/min and end of the cut. = 8.143in³/min
Explanation:
check attached files below for answer.
Answer:
(a) dynamic viscosity =
(b) kinematic viscosity =
Explanation:
We have given temperature T = 288.15 K
Density
According to Sutherland's Formula dynamic viscosity is given by
, here
μ = dynamic viscosity in (Pa·s) at input temperature T,
= reference viscosity in(Pa·s) at reference temperature T0,
T = input temperature in kelvin,
= reference temperature in kelvin,
C = Sutherland's constant for the gaseous material in question here C =120
= 291.15
when T = 288.15 K
For kinematic viscosity :