Answer:
Given that
Mass flow rate ,m=2.3 kg/s
T₁=450 K
P₁=350 KPa
C₁=3 m/s
T₂=300 K
C₂=460 m/s
Cp=1.011 KJ/kg.k
For ideal gas
P V = m R T
P = ρ RT
ρ₁=2.71 kg/m³
mass flow rate
m= ρ₁A₁C₁
2.3 = 2.71 x A₁ x 3
A₁=0.28 m²
Now from first law for open system
For ideal gas
Δh = CpΔT
by putting the values
Q= - 45.49 KJ/kg
Q =- m x 45.49 KW
Q= - 104.67 KW
Negative sign indicates that heat transfer from air to surrounding
Answer:
1500Ω
Explanation:
Given data
voltage = 15 V
total Resistance = 4000Ω
potential drop V = 9.375 V
To find out
R2
Solution
we know R1 +R2 = 4000Ω
So we use here Ohm's law to find out current I
current = voltage / total resistance
I = 15 / 4000 = 3.75 × 
A
Now we apply Kirchhoffs Voltage Law for find out R2
R2 = ( 15 - V ) / current
R2 = ( 15 - 9.375 ) / 3.75 ×
R2 = 1500Ω
Answer: C. Problem identification, solution design, implementation, evaluation.
Explanation:
Answer:
$1.38
Explanation:
She will spend $25 million in 3 years at 10% interest is a case of Future Value of Annuity.
Therefore,
FV = A*((1+r)^n-1)/r
Where A = 25,000,000
r=10%=0.1
n=3
FV= 25000000*((1+0.1)^3-1)/0.1
FV=25000000*(1.331-1)/0.1
FV=25000000*(0.331/0.1)
FV=25000000*3.31
FV=$82,750,000
So it is estimated that 20million cars passes through the toll per year
Therefore,
Toll per vehicle per year = 82750000/2000000
=$4.14
Toll for the duration of the project
=4.14/3 =$1.38
