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Citrus2011 [14]
2 years ago
6

If a child of mass 60.6 kg sits in a seat, what is

Physics
1 answer:
Semmy [17]2 years ago
4 0

The Tension in the chain is 593.88 N

<h3> Tension:</h3>

This can be defined as a pulling force, transmitted to a rope or a string.

The Tension in the chain can be calculated using the formula below.

Formula:

  • T = mg................................... Equation 1

Where:

  • T = Tension in the chain
  • m = mass of the child
  • g = acceleration due to gravity.

From the question,

Given:

  • m = 60.6 kg
  • g = 9.8 m/s²

Substitute these values into equation 1

  • T = 60.6(9.8)
  • T = 593.88 N

Hence, the Tension in the chain is 593.88 N

Learn more about tension here: brainly.com/question/24994188

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Choose the correct explanation of whether the discovery should be considered reasonable or surprising.
earnstyle [38]

Answer: a. This would be exciting, but not surprising. Heat from Martian volcanoes may well be enough to melt water under the Mars' surface.

Explanation: It was recently observed by a team of geological researchers that there exist some activity at the crust of the planet mars. This activity are volcanic in nature and estimated to be about 10kilometers large. Also this volcanic eruptions in the planet mars core are described as among the largest in our solar system. Therefore it won't be a surprise that Heat from Martian volcanoes may well be enough to melt water under the Mars' surface.

6 0
4 years ago
If the mass of an object is 8 kg and its momentum is -80 kgm/s, what is its velocity?
Dimas [21]

An object's momentum is the product of its mass and its velocity:

p = mv

p is its momentum, m is its mass, and v is its velocity.

Given values:

p = -80kg×m/s

m = 8kg

Plug in these values and solve for v:

-80 = 8v

v = -10m/s

Choice D

4 0
3 years ago
The tops of the towers of the Golden Gate Bridge in San franciscoo , are 227 m above the water. Suppose a worker drops a 655 g w
yaroslaw [1]

Answer:

Kinetic energy is 1425.11 J.

Explanation:

Given:

Mass of the wrench is, m=655\ g=0.655\ kg

Height of fall is, h=227\ m

Force of resistance is, F=0.141\ N

Now, the total energy at the top is equal to the potential energy of the wrench at the top since the kinetic energy at the top is 0.

Now, potential energy at the top is given as:

U=mgh\\U=0.655\times 9.8\times 227\\U=1457.113\ J

Now, the potential energy at the top is converted to kinetic energy at the bottom and some energy is wasted in overcoming the resistance force by air.

Potential Energy = Kinetic energy + Energy to overcome resistance.

⇒ Kinetic energy = Potential Energy - Energy to overcome resistance.

Energy to overcome resistance force is the work done by the wrench against the resistance force and is given as:

W_{res}=Fh=0.141\times 227=32.007\ J

Therefore, Kinetic energy at the bottom is given as:

K=U-W_{res}\\\\K=1457.113\ J - 32.007\ J\\\\K=1425.106\approx1425.11\ J

Hence, the kinetic energy of the wrench be when it hits the water is 1425.11 J.

7 0
4 years ago
PLEASE HELP ME WITH MY HOMEWORK!!!!!
IgorC [24]

Known :

l = 7 cm

w = 4 cm

Asked :

h = ...?

Answer :

V = B triangle × h (long)

35 = ½ × 4 × h × 7

35 = ½ × 28 × h

35 = 14 h

h = 35 ÷ 14

h = 2,5 cm

Sorry if I am wrong, I only study

5 0
3 years ago
A ball is dropped from rest at point O. After falling for some time, it passes by a window of height 3.3 m and it does so in 0.2
stiv31 [10]

Answer:

Speed at which the ball passes the window’s top = 10.89 m/s

Explanation:

Height of window = 3.3 m

Time took to cover window = 0.27 s

Initial velocity, u = 0m/s

We have equation of motion s = ut + 0.5at²

For the top of window (position A)

                     s_A=0\times t_A+0.5\times 9.81t_A^2\\\\s_A=4.905t_A^2

For the bottom of window (position B)

                     s_B=0\times t_B+0.5\times 9.81t_B^2\\\\s_A=4.905t_B^2

\texttt{Height of window=}s_B-s_A=3.3\\\\4.905t_B^2-4.905t_A^2=3.3\\\\t_B^2-t_A^2=0.673

We also have

                 t_B-t_A=0.27

Solving

         t_B=0.27+t_A\\\\(0.27+t_A)^2-t_A^2=0.673\\\\t_A^2+0.54t_A+0.0729-t_A^2=0.673\\\\t_A=1.11s\\\\t_B=0.27+1.11=1.38s

So after 1.11 seconds ball reaches at top of window,

       We have equation of motion v = u + at

                                     v_A=0+9.81\times 1.11=10.89m/s

Speed at which the ball passes the window’s top = 10.89 m/s                

7 0
4 years ago
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