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Citrus2011 [14]
2 years ago
6

If a child of mass 60.6 kg sits in a seat, what is

Physics
1 answer:
Semmy [17]2 years ago
4 0

The Tension in the chain is 593.88 N

<h3> Tension:</h3>

This can be defined as a pulling force, transmitted to a rope or a string.

The Tension in the chain can be calculated using the formula below.

Formula:

  • T = mg................................... Equation 1

Where:

  • T = Tension in the chain
  • m = mass of the child
  • g = acceleration due to gravity.

From the question,

Given:

  • m = 60.6 kg
  • g = 9.8 m/s²

Substitute these values into equation 1

  • T = 60.6(9.8)
  • T = 593.88 N

Hence, the Tension in the chain is 593.88 N

Learn more about tension here: brainly.com/question/24994188

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A package of chips weighs 45 grams. How much is that in kilograms?
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2 years ago
In the diagram, q1= +8.0 C, q2= +3.5 C, and q3 = -2.5 C. q1 to q2 is 0.10 m, q2 to q3 is 0.15 m. What is the net force on q2? La
yulyashka [42]

Answer:

f(t) =  28,7 [N]

Explanation: IMPORTANT NOTE: IN PROBLEM STATEMENT CHARGES ARE IN C (COULOMBS) AND IN THE DIAGRAM IN μC. WE ASSUME CHARGES ARE IN μC.

The net force on +q₂  is the sum of the force of +q₁  on +q₂ ( is a repulsion force since charges of equal sign repel each other ) and the force of -q₃ on +q₂ ( is an attraction force, opposite sign charges attract each other)

The two forces have the same direction to the right of charge q₂, we have to add them

Then

f(t) = f₁₂ + f₃₂

f₁₂ = K * ( q₁*q₂ ) / (0,1)²

q₁  = + 8 μC     then   q₁ = 8*10⁻⁶ C

q₂ =  + 3,5 μC  then  q₂ = 3,5 *10⁻⁶ C

K = 9*10⁹  [ N*m² /C²]

f₁₂ = 9*10⁹ * 8*3,5*10⁻¹²/ 1*10⁻²   [ N*m² /C²]* C*C/m²

f₁₂ = 252*10⁻¹ [N]

f₁₂ = 25,2 [N]

f₃₂ =  9*10⁹*3,5*10⁻⁶*2,5*10⁻⁶ /(0,15)²

f₃₂ =  78,75*10⁻³/ 2,25*10⁻²

f₃₂ =  35 *10⁻¹

f₃₂ =  3,5 [N]

f(t) =  28,7 [N]

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3 years ago
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