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3 years ago

10. Well into the twentieth century, many scientists believed the ocean floor was A. rocky. B. round. C. flat. D. sandy.

2 answers:

8 0

In the 20th century, the scientist believed that the floor of the ocean floor is flat. But later on discovered that their theory is wrong. The ocean floor is not flat and featureless. One technology helped the scientist to study in advance and in details the real feature of the ocean floor. They used sound waves to know the distance of the water from floor level to the top. They also discovered that ranges of mountains lies under the ocean. Sonar was one of the technologies they used to study the sound waves emitted by the ocean. Hope i was helpful :)

denpristay [2]3 years ago

3 0

C. flat
the ocean was believed to be flat before they had sonar

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Consider the reaction of A(g) + B(g) + C(g) => D(g) for which the following data were obtained:

Drupady [299]

Answer:

$r = k [A]^{2}[B]^{2}$

Explanation:

A + B + C ⟶ D

$\text{The rate law is } r = k [A]^{m}[B]^{n}[C]^{o}$

Our problem is to determine the values of m, n, and o.

We use the method of initial rates to determine the order of reaction with respect to a component.

(a) Order with respect to A

We must find a pair of experiments in which [A] changes, but [B] and C do not.

They would be Experiments 1 and 2.

[B] and [C] are constant, so only [A] is changing.

$\begin{array}{rcl}\dfrac{r_{2}}{r_{1}} & = & \dfrac{ k[A]_{2}^{m}}{ k[A]_{1}^{m}}\\\\\dfrac{2.50\times 10^{-2}}{6.25\times 10^{-3}} & = & \dfrac{0.100^{m}}{0.0500^{m}}\\\\4.00 & = & 2.00^{m}\\m & = & \mathbf{2}\\\end{array}\\\text{The reaction is 2nd order with respect to A}$

(b) Order with respect to B

We must find a pair of experiments in which [B] changes, but [A] and [C] do not. There are none.

They would be Experiments 2 and 3.

[A] and [C] are constant, so only [B] is changing.

$\begin{array}{rcl}\dfrac{r_{3}}{r_{2}} & = & \dfrac{ k[B]_{3}^{n}}{ k[B]_{2}^{n}}\\\\\dfrac{1.00\times 10^{-1}}{2.50\times 10^{-2}} & = & \dfrac{0.100^{n}}{0.0500^{n}}\\\\4.00 & = & 2.00^{n}\\n & = & \mathbf{2}\\\end{array}\\\text{The reaction is 2nd order with respect to B}$

(c) Order with respect to C

We must find a pair of experiments in which [C] changes, but [A] and [B] do not.

They would be Experiments 1 and 4.

[A] and [B] are constant, so only [C] is changing.

$\begin{array}{rcl}\dfrac{r_{4}}{r_{1}} & = & \dfrac{ k[C]_{4}^{o}}{ k[C]_{1}^{o}}\\\\\dfrac{6.25\times 10^{-3}}{6.25\times 10^{-3}} & = & \dfrac{0.0200^{o}}{0.0100^{o}}\\\\1.00 & = & 2.00^{o}\\o & = & \mathbf{0}\\\end{array}\\\text{The reaction is zero order with respect to C.}\\\text{The rate law is } r = k [A]^{2}[B]^{2}$

5 0

3 years ago

This is due today so please help me

Nonamiya [84]

B north to south. Hope this helps

7 0

3 years ago

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Excess silver(I) nitrate was added to a 8.500 g mixture containing some amount of barium chloride, and 7.123 g of silver chlorid

dsp73

Answer:

60.88%

Explanation:

The balanced equation of the reaction is given as;

2 AgNO3 (aq) + BaCl2 (aq) → 2 AgCl (s) + Ba(NO3)2 (aq)

Since AgNO3 is in excess, the limiting reactant is BaCl2. From the reaction;

1 mol of BaCl2 produces 2 mol of AgCl

Converting to masses;

Mass = Number of mol * Molar mass

BaCl2;

Mass = 1 * 208.23 g/mol = 208.23 g

AgCl;

Mass = 2 * 143.32 g/mol = 286.64 g

208.23 g BaCl2 produces 286.64 g of AgCl

x g BaCl2 produces 7.123 g of AgCl

Solving for x;

x = 7.123 * 208.23 / 286.64 = 5.1745 g

Mass percent = Mass / Total mass of Mixture * 100

Mass Percent = 5.1745 / 8.500 = 0.6088 * 100 = 60.88%

8 0

3 years ago

Glucose molecules bond together in a process known as dehydration synthesis. What happens in this process?. . Water is used as a

IRISSAK [1]

"A water molecule is formed from the hydrogen and oxygen atoms removed" is what happens in the process described in the question. The correct option among all the options that are given in the question is the second option. I hope the answer has actually come to your great help.

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3 years ago

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In the reaction Mg+Cl2=MgCl2 what should be the coefficient for Cl2

oksano4ka [1.4K]

It should just be one for it to be balanced.

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3 years ago

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