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Shkiper50 [21]
3 years ago
10

What is in group 7 period 4

Chemistry
2 answers:
stira [4]3 years ago
8 0

Answer:

Manganese

Explanation:

igor_vitrenko [27]3 years ago
5 0
Well group 7 are all known elements of transition metals Rf is period 4 :) pls give me brainliest
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Answer: 4000000000

because 20X200000000=4000000000

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What is the mass, in grams, of a liquid having a density of 1.50g/mL and a volume of 3500mL
mojhsa [17]

Answer:

5,250g

Explanation:

Density = Mass / Volume

*Note: mass = x

1.50g/mL = x / 3500mL

multiply 3500mL on both sides

1.50g/mL * 3500mL = 3500mL(x) / 3500mL

cancel units

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What number of atoms of phosphorus are present in 1.00g of each of the compounds in exercise 40?
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Answer: 1.095 * 10^22 atoms of P.

Explanation:

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What symbol of the periodic table is Diamond?
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6 0
3 years ago
If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
Nikolay [14]

Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

3 0
3 years ago
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