All categories

2 years ago

Is this the correct formula for magnesium acetate? Mg(C2H3O)2

Chemistry

1 answer:

andre [41]2 years ago

4 0

Answer:

Explanation:

magnesium acetate= Mg(C2H3O2)2

You might be interested in

Which of the following describes a compound?

Gemiola [76]

A compound is two or more chemically combined elements. Fore example NaCl, CO2, H2O

8 0

3 years ago

a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re

Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Given : 59.4 g of $H_2SO_4$ in 100 g of solution

moles of $H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61$

Volume of solution = $\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.61\times 1000}{54.6ml}=11.2M$

To calculate the volume of acid, we use the equation given by neutralisation reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock acid which is $H_2SO_4$

$M_2\text{ and }V_2$ are the molarity and volume of dilute acid which is $H_2SO_4$

We are given:

$M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL$

Putting values in above equation, we get:

$11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL$

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0

3 years ago

A tree trunk floating in the water<br> Balanced<br> Or<br> Unbalanced

mars1129 [50]

Answer:

Balanced

Explanation:

Please help me by marking me brainliest. I'm one away :)

3 0

3 years ago

What can you infer about copper's properties?

tiny-mole [99]

Answer:

good electrical conductor

lustre in appearance

7 0

3 years ago

The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant

enot [183]

Answer: $C=\frac{\pi}{R\times T}$

Explanation:-

Osmotic pressure is a colligative property which depends on the amount of solute added.

$\pi=CRT$

$\pi$ = osmotic pressure = 5.1 atm

C= concentration in Molarity

R= solution constant = 0.0821 Latm/Kmol

T= temperature = 312 K

$C=\frac{\pi}{R\times T}$

$C=\frac{5.1atm}{0.0821Latm/Kmol\times 312K}=0.2mol/L$

Thus the equation for calculating the molarity of this solution is $C=\frac{\pi}{R\times T}$

4 0

3 years ago