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Gemiola [76]
3 years ago
12

Why does the elements of group 17 appear as diatomic molecules?

Chemistry
1 answer:
julsineya [31]3 years ago
4 0

Answer:

To gain stability.

Explanation:

Atoms are stable when they have complete octet means they have 8 valance electrons.

The halogens elements are present  in group seventeen. All atoms of halogen elements have seven valance electrons. They need one more electron to complete the octet and get stable.

That's why all halogens atoms are very reactive because they react with other atoms complete the octet and present in the form of diatomic molecule.

The halogen atoms react with metals and form ionic compound.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.  Both atoms are combine by electrostatic attraction.

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An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally through a distance of 6.00 m. What
TEA [102]

Answer:

The answer to the question is

The change in the kinetic energy of the object is 600 J

Explanation:

The known variables are,

Mass of object, m = 100 kg

Force of object, F = 100 N

The relation for kinetic energy = KE = \frac{1}{2} * m * v^{2} = 0.5·m·v²

Therefore to find v we first find the acceleration from

F = m·a =10.0 kg × a = 100 N,

Where a = acceleration of the object =100/10 = 10 m/s²

To find the velocity, v, we use the relationship

v² = u² + 2 × a × S, where S is the distance of motion = 6.00 m and u is the initial velocity, u = 0 m/s, therefore

v² = 0 + 2 × 10 m/s² × 6 m = 120 m²/s² or v = 10.95 m/s

Therefore KE = 0.5 × 10 kg × (10.95 m/s)² = 600 J

where the initial velocity, u = 0 m/s

Initial kinetic energy of the object = KE₁ = 0.5 × 10 × 0² = 0

The change in kinetic energy of the object = 600 J - 0 J = 600 J

5 0
4 years ago
Determine molar mass of Mn (ClO3)3
goldenfox [79]
M(Mn(ClO3)3)=(54.938)+(35.45x3)+(15.999x9)
M(Mn(ClO3)3)=305.279 g/mol
8 0
3 years ago
Oxygen gas, generated by the reaction 2KClO3(s)->2KCl(s)+3O2(g) is collected over water at 27°C in a 1.55 L vessel at a total
KonstantinChe [14]

Answer:

Explanation:

Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.

PT = Poxygen +Pwater

At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)

762 mmHg = Poxygen + 21.1 mmHg

Poxygen = 762 mmHg - 21.1 mmHg

Poxygen =741 mmHg

Convert the corrected pressure to atmospheres.

(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm

Use the ideal gas law to find out how many moles of gas were produced:

PV = nRT (remember to put volume in liters and temperature in Kelvin)

(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)

n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)

n = 7.69 X 10-4 mol

Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.

(7.69 X 10-4 mol) (32.0 g / 1 mol) = 2.46 X 10-2 g

4 0
3 years ago
How does the arrangement of particles in a gas differ from the arrangements in liquids and solids?
Paladinen [302]
The arrangement of particles in a gas is random. they have no orderly arrangement and are free to move around while the particles in solid are in an orderly and rigid arrangement and cannot move about. particles in liquid are also arranged orderly but are not rigid
3 0
4 years ago
phosphorus trifluoride is formed from its elements P4 (s) F2 (g) ---> PF3 (g) how many grams of fluorine are needed to react
Oksi-84 [34.3K]

This is an incomplete question, here is a complete question.

Phosphorus trifluoride is formed from its elements.

P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

How many grams of fluorine are needed to react with 6.20 g of phosphorus?

Answer : The mass of F_2 needed are, 11.4 grams.

Explanation : Given,

Mass of P_4 = 6.20 g

Molar mass of P_4 = 124 g/mol

Molar mass of F_2 = 38 g/mol

First we have to calculate the moles of P_4

\text{Moles of }P_4=\frac{\text{Given mass }P_4}{\text{Molar mass }P_4}

\text{Moles of }P_4=\frac{6.20g}{124g/mol}=0.05mol

Now we have to calculate the moles of F_2

The balanced chemical equation is:

P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

From the balanced reaction we conclude that

As, 1 mole of P_4 react with 6 moles of F_2

So, 0.05 moles of P_4 react with 0.05\times 6=0.30 moles of F_2

Now we have to calculate the mass of F_2

\text{ Mass of }F_2=\text{ Moles of }F_2\times \text{ Molar mass of }F_2

\text{ Mass of }F_2=(0.30moles)\times (38g/mole)=11.4g

Therefore, the mass of F_2 needed are, 11.4 grams.

4 0
3 years ago
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