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3 years ago

5

Classify chunky peanut butter as an element, a compound, a heterogeneous mixture, or a homogeneous mixture.

1 answer:

andrezito [222]3 years ago

4 0

Chunky peanut butter is a mixture which is NOT uniform throughout, so it is a heterogeneous mixture.

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Can some answer this please?

marysya [2.9K]

Answer:

b

Explanation:

it's b because I just went over that frome my class and got it correct

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3 years ago

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. Which type of energy is involved in the operation of simple machines?

quester [9]

Input an output energy

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3 years ago

How many milliliters of 0.0630 m edta are required to react with 50.0 ml of 0.0110 m cu2 ?

gizmo_the_mogwai [7]

Moles Cu+2 = M * V
= 0.05 L * 0.011 m
= 0.00055 moles

when the molar ratio of Cu2+: EDTA = 1:1 so moles od EDTa also =0.00055 moles

and when the Molarity of EDTa = 0.0630 M

∴ Volume of EDTA = moles / Molarity
= 0.00055 / 0.0630
= 0.0087 L = 8.7 L

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3 years ago

Equal volumes of H2 and o2 are placed in a balloon and then ignited. Assuming that the reaction goes to completion, which gas wi

Anastasy [175]

You will have excess O2. The ideal gas law dictates that all other variables kept the same, equal volume means equal number of moles.

7 0

3 years ago

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Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]

madreJ [45]

Answer:

$Mn^{2+}$ : - F . $[Ar]3d^{5}$

$Hg^{2+}$ : - G. $[Xe]4f^{14}5d^{10}$

$La^{3+}$ : - D. $[Xe]$

$Fe^{3+}$ : - F. $[Ar]3d^{5}$

$Ag^{+}$ : - C. $[Kr]4d^{10}$

$Co^{3+}$ : - E. $[Ar]3d^{6}$

Explanation:

The electronic configuration of the element Mn is:-

$[Ar]3d^{5}4s^2$

For, $Mn^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Hg is:-

$[Xe]4f^{14}5d^{10}6s^2$

For, $Hg^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Xe]4f^{14}5d^{10}$

The electronic configuration of the element La is:-

$[Xe]5d^{1}6s^2$

For, $La^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Xe]$

The electronic configuration of the element Fe is:-

$[Ar]3d^{6}4s^2$

For, $Fe^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Ag is:-

$[Kr]4d^{10}5s^1$

For, $Ag^{+}$ , 1 electron is lost, thus the configuration is:-

$[Kr]4d^{10}$

The electronic configuration of the element Co is:-

$[Ar]3d^{7}4s^2$

For, $Co^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{6}$

7 0

3 years ago