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3 years ago

Which type of electromagnetic radiation has the shortest wavelength?

Physics

1 answer:

ankoles [38]3 years ago

4 0

Answer:

Its Gamma radiation my dude :D

Explanation:

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A waitperson carrying a tray with a platter on it tips the tray at an angle of 12 degrees below the horizontal. If the gravitati

Tasya [4]

Answer:1.04 N

Explanation:

Given

Gravitational Force on the Platter is $5 N$

Tray makes an angle of $\theta =12^{\circ}$

This gravitational Force has components along and Perpendicular to Platter

Perpendicular Force $W_p=W\cos \theta$

$W_p=5\times \cos 12=4.89 N$

Along the Tray

$W_{along}=W\sin \theta$

$W_{along}=5\times \sin 12=1.04 N$

Thus 1.04 N is the magnitude of force that will cause Platter to slide down

7 0

3 years ago

A 1000 kg car’s velocity increases from 5 m/s to 10 m/s. What is the change to the car’s kinetic energy? Show your work.

katen-ka-za [31]

Answer:

k. e. = 1/2 mv^2

1/2 * 1000 * (5)^2

1/2 * 1000 * 25

12500 joules

k. e. = 1/2 mv^2

1/2 * 1000 * (10)^2

1/2 * 1000 * 100

50000

change in k. e. = final - initial

50000 - 12500

= 37500 joules

hope it helps you

3 0

3 years ago

A pump of power 1500W is used for 5 mins the energy supplied by the pump is

Anika [276]

Answer:

300W

Explanation:

from my years in middle school, i have learned the equation is energy =power*time is 300W

7 0

4 years ago

You indicate that a symbol

Goryan [66]

Answer:

B. over the symbol.

Explanation:

vectors are represented with a symbol carrying an arrow head with also indicates direction

8 0

3 years ago

A yo-yo is made from two uniform disks, each with mass m and radius R, connected by a light axle of radius b. A light, thin stri

schepotkina [342]

Answer:

linear acceleration

$a = \frac{2g}{2 + \frac{R}{b}}$

angular acceleration

$\alpha = \frac{2g}{R(2 + \frac{R}{b})}$

Explanation:

As we know that the force due to tension force is upwards while weight of the disc is downwards

so we will have

$2mg - T = 2ma$

also we have

$Tb = (\frac{1}{2}mR^2 + \frac{1}{2}mR^2)\alpha$

now we have

$Tb = mR^2(\frac{a}{R})$

$T = \frac{mRa}{b}$

now we have

$2mg = (2ma + \frac{mRa}{b})$

$a(2 + \frac{R}{b}) = 2g$

so we have

linear acceleration

$a = \frac{2g}{2 + \frac{R}{b}}$

angular acceleration

$\alpha = \frac{2g}{R(2 + \frac{R}{b})}$

4 0

3 years ago