Answer:
a) about 14.577 kg
b) 300 N
Explanation:
b) In order for the acceleration to be the same for each mass, the 800 N force must be divided between the boxes in proportion to their mass. That is, the net force on the 5M mass must be 5/8 of the total force, or 500 N. Then the tension in the rope is 800 N -500 N = 300 N, which is 3/8 of 800 N.
Tension: 300 N
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a) The total mass is 8M, and the total normal force on the floor is ...
F = ma = (8M)(9.8 m/s^2)
The friction force is 0.7 times this, and is equal to the 800 N force pulling on the boxes.
800 N = (8M)(9.8 m/s^2)(0.7)
M = 800/(8·9.8·0.7) kg ≈ 14.577 kg
Answer:
Distance is 100m, displacement is 0m
Explanation:
Distance is how much you travelled in total (100m)
Displacement is when you compare your final and initial positions.
It is usually Final position - Initial position.
Since you start and finish at the same point, it would be 0 - 0 = 0m
So the displacement is 0m.
Answer:
B.
Explanation:
I'm not sure if it's the right answer but I think it is. I hope I helped out in some way.
Answer:
1428.6m/s²
Explanation:
Given parameters:
Force applied on the body = 40N
Mass of the body = 28g
1000g = 1kg
28g will therefore be 0.028kg
Unknown:
Acceleration = ?
Solution:
To solve this problem, we use the expression derived from Newton's second law of motion.
Force = mass x acceleration
Insert the parameters and solve;
40 = 0.028 x acceleration
Acceleration = 
= 1428.6m/s²
