Answer:
56.28 g
Explanation:
First change the grams of oxygen to moles.
(50.00 g)/(32.00 g/mol) = 1.5625 mol O₂
You have to use stoichiometry for the next part. Looking at the equation, you can see that for every 2 moles of H₂O, 1 mole of O₂ is produced. Convert from moles of O₂ to moles of H₂O using this relation.
(1.5625 mol O₂) × (2 mol H₂O/1 mol O₂) = 3.125 mol H₂O
Now convert moles of H₂O to grams.
(3.125 mol) × (18.01 g/mol) = 56.28125 g
Convert to significant figures.
56.28125 ≈ 56.28
B. It is the heat required to change a gram of substance from solid to liquid
Answer:
2H₂O₂ → 2H₂O + O₂
24.7 L are the liters of formed oxygen.
Explanation:
We state the reaction:
2H₂O₂ → 2H₂O + O₂
2 moles of peroxide decompose to 2 moles of water and 1 mol of oxygen gas.
We convert the mass to moles: 75 g . 1 mol / 34 g = 2.20 moles
As ratio is 2:1, per 2.20 moles of peroxide I would produce the half of moles, of O₂ → 2.20 /2 = 1.10 moles
We convert the moles to mass → 1.10 mol . 32 g / 1 mol = 35.3 g
Let's use oxygen's density to find out the volume
δ O₂ = 1.429 g/L (mass/volume)
35.3 g . 1L / 1.429g = 24.7 L
B. Increase the volume (in other words, decrease the pressure).
A is wrong because as temperature decreases, the reaction will shift to the left as the system is endothermic (positive delta H).
C. is wrong because as O2 gas is added, the reaction will shift to the left in order to relieve the stress on the system.
D. is wrong because a catalyst will increase the rate of the reaction by decreasing the activation energy. It doesn't affect equilibrium.
B is correct because the left side has two moles of gas while the right side has three moles of gas. Thus, when pressure is decreased (volume is increased--they are inversely related), the system will shift in the direction with more moles of gas.
Answer:
Concentration of the sugar in the solution increases
