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maksim [4K]
3 years ago
13

Why can television satellites, which broadcast information as electromagnetic radiation, send signals from the vacuum of space?

a because electromagnetic radiation increases as the distance increases b because electromagnetic radiation does not need a medium to travel through c because space does not provide a medium that will block the satellite signals eliminate d because space is so vast that light waves can spread out to their full size and strength?
Physics
2 answers:
neonofarm [45]3 years ago
5 0
The answer is b. Electromagnetic waves do not need a medium to travel through.
iren [92.7K]3 years ago
4 0

Answer:

<u>B</u><u> because electromagnetic radiation does not need a medium to travel through.</u>

Explanation:

Long ago, we (humans) used to think that every wave needed a medium to travel trough. The hypothetical electromagnetic medium was called Aether, but this brought some predictions of the wave behavior that couldn't be measured. One famous experiment made trying to measure one of this predictions was the Michelson Morley experiment, that tried to measure the  Aether drag, the drag of the medium made by the Earth as it travels trough it, kinda like a ship making waves as passed by a canal. So, all this experiments didn't give any results, and no one knew why. Then it came Albert Einstein. In 1905 he published a revolutionary work, that we today call the Special Relativity Theory, that does not needs an aether to explain how the light travels trough space, and its a theory accepted by all scientist (or almost all) today.

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A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci
Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

\vec v_1=(x_1,y_1)

\vec v_2=(x_2,y_2)

The sum of the vectors is:

\vec v=(x_1+x_2,y_1+y_2)

The magnitude of a vector can be calculated by

d=\sqrt{x^2+y^2}

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

\vec v_1=(-34,0)

The wind blows at 19 m/s south, thus:

\vec v_2=(0,-19)

The sum of both velocities gives the resultant velocity:

\vec v =(-34,-19)

The magnitude of this velocity is:

d=\sqrt{(-34)^2+(-19)^2}

d=\sqrt{1156+361}=\sqrt{1517}

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0
3 years ago
A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o
dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  m_1 = 81.14 \ kg

Explanation:

From the question we are told that

   Mass of the first block is  m_1 = 100 \  kg

   The height is  s =  1.0 \  m

   The time it takes it is  t = 1.40 \  s

 Generally from kinematic equation

       s =  ut + \frac{1}{2} at^2

Here u  is the initial velocity which zero given that it was at rest initially

So

     s =  0 * t + \frac{1}{2} at^2

=>  s =   \frac{1}{2} at^2

=> 1 =   \frac{1}{2}*  a *  (1.40 )^2

=>  a = 1.0204 \  m/s^2

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      mg - T = ma

=>   T  =  m g - ma

=>   T  =  m(g - a)

=>   T  =  877.96 \  N

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     T - m_1g  =  m_1 a

=>   877.96  =  m_1 (a + g)

=>   877.96  =  m_1 (1.0204  + 9.8 )

=>   m_1 = 81.14 \ kg

5 0
3 years ago
Can you put hot water in a insulated gatorade cooler
Elina [12.6K]
Yes is the answer for you
5 0
3 years ago
Two charged particles are projected into a magnetic field that is perpendicular to their initial velocities. If the charges are
Svetllana [295]

Answer:

The two charged particles are opposite charge (one positive, the other negative)

Explanation:

This can be explained through Fleming's left hand rule. As we know in Fleming's LH rule

Thumb: represent motion of the charge

Fore finger: direction of magnetic field

Centre finger: direction of current

In this case, the direction of magnetic field is in one way (perpendicular to direction of the particles motion)

If the charge is positive, equivalently it's direction is the same as the direction of current. If the charge is negative, it's direction is opposite the direction of current.

Using the fleming left hand rule, we'll see that as we change the direction of current without changing the direction of field, the direction of motion will change towards the opposite way.

For example, let's say the particles is moving away from you and the magnetic field is from left to right:

If the charge is positive (hence direction of current is away from you), the particles will move downward.

If the charge is negative (hence direction of current is toward you), the particles will move upward.

With these evidence, no doubt that the two particles have different charges.

7 0
4 years ago
A charge of +1 coulomb is place at the 0 cm mark of a meter stick. A charge of +4 coulombs is placed at the 100 cm mark of the s
UkoKoshka [18]

As per the question the charge of one coulomb is at 0 cm of the metre stick.the second charge of 4 coulomb is situated at at 100 cm of metre stick.

hence the separation distance between them is 100 cm.

now as per the question a proton is set up  between them in such a way that the net force on it is zero

let the charge of proton is q coulomb let the proton is situated at distance of x cm from the charge 1 coulomb.hence it is situated at a distance of 100-x cm from the charge 4 coulomb.

the force exerted by 1 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}

the force exerted by 4 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{q*4}{[100-x]^2}

as the net force is zero,hence-

\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}=\frac{1}{4\pi\epsilon} \frac{4*q}{[100-x]^2}

=\frac{1}{x^2} =\frac{4}{[100-x]^2}


x^2=\frac{[100-x[^2}{4}[/tex[tex]x=\frac{100-x}{2}

3x=100

x=\frac{100}{3}

=33.33333cm   [ans]







4 0
3 years ago
Read 2 more answers
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